Question Number 50674 by mr W last updated on 18/Dec/18 $${Find}\:{the}\:{maximum}\:{area}\:{of}\:{a}\:{triangle} \\ $$$${inscribed}\:{in}\:{an}\:{ellipse}\:{with}\:{parameters} \\ $$$${a}\:{and}\:{b}. \\ $$ Commented by ajfour last updated on 18/Dec/18 Commented…
Question Number 181736 by mnjuly1970 last updated on 29/Nov/22 Answered by universe last updated on 30/Nov/22 $${see}\:{question}\:\mathrm{172437} \\ $$ Terms of Service Privacy Policy Contact:…
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Question Number 181711 by Ari last updated on 28/Nov/22 Commented by mr W last updated on 29/Nov/22 $$\frac{\mathrm{9}}{\mathrm{53}+\mathrm{9}}×\mathrm{48}=\frac{\mathrm{216}}{\mathrm{31}} \\ $$$$\frac{\mathrm{9}}{\mathrm{53}−\mathrm{9}}×\mathrm{48}=\frac{\mathrm{108}}{\mathrm{11}} \\ $$$$\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{\mathrm{216}}{\mathrm{31}}+\frac{\mathrm{108}}{\mathrm{11}}\right)=\frac{\mathrm{2862}}{\mathrm{341}}\approx\mathrm{8}.\mathrm{4}<\mathrm{16} \\ $$$$\Rightarrow{triangle}\:{with}\:{height}\:\mathrm{16}\:{impossile}! \\…
Question Number 181673 by cherokeesay last updated on 28/Nov/22 Answered by HeferH last updated on 28/Nov/22 $${A}\:=\:\frac{\left({r}_{\mathrm{1}} \:+\:{r}_{\mathrm{2}} \right){BD}}{\mathrm{2}}\: \\ $$$$\:{BD}\:=\:\mathrm{5}\:−\:\left(\frac{\mathrm{16}}{\mathrm{5}}\:+\:\mathrm{1}\right)\:=\:\frac{\mathrm{25}\:−\:\mathrm{21}}{\mathrm{5}}\:=\:\frac{\mathrm{4}}{\mathrm{5}} \\ $$$$\:{A}\:=\:\frac{\mathrm{1}}{\mathrm{2}}\left(\mathrm{2}\:+\:\frac{\mathrm{12}}{\mathrm{5}}\right)\frac{\mathrm{4}}{\mathrm{5}}\:\:=\:\frac{\mathrm{44}}{\mathrm{25}}\:{u}^{\mathrm{2}} \\ $$…
Question Number 181651 by mr W last updated on 28/Nov/22 Commented by Acem last updated on 05/Dec/22 $${Did}\:{you}\:{both}\:{believe}\:{him}\:{with}\:{all}\:{your}\:{minds}? \\ $$$${He}\:{just}\:{trying}\:{to}\:{make}\:{you}\:{feel}\:{remorse}\:{and} \\ $$$$\:{give}\:{the}\:{goat}\:{eternal}\:{rest}\:{and}\:{then}\:{invite}\:{him} \\ $$$$\:{to}\:{a}\:{barbecue} \\…
Question Number 50577 by behi83417@gmail.com last updated on 17/Dec/18 Commented by behi83417@gmail.com last updated on 17/Dec/18 $$\measuredangle{ABC}=\mathrm{90},{AC}=\mathrm{1},{AD}=\frac{\sqrt{\mathrm{3}}}{\mathrm{6}}\:\left({angular}\:{bisector}\right). \\ $$$$\Rightarrow\:\:\:{AB}=?\:\:,{BC}=? \\ $$ Answered by ajfour last…
Question Number 50561 by ajfour last updated on 17/Dec/18 Commented by ajfour last updated on 17/Dec/18 $${Find}\:{radius}\:{r}\:{of}\:{dashed}\:{circles} \\ $$$$\left({all}\:{equal}\right),\:{given}\:\boldsymbol{{n}}\:{and}\:\boldsymbol{{R}}. \\ $$ Answered by tanmay.chaudhury50@gmail.com last…
Question Number 116093 by Engr_Jidda last updated on 30/Sep/20 $${Find}\:{the}\:{equation}\:{of}\:{a}\:{circle}\:{which}\:{touches} \\ $$$${x}−{axis}\:{and}\:{the}\:{line}\:{y}={x}\:{in}\:{the}\:\mathrm{1}^{{st}} \:{quadrant}. \\ $$$${Determine}\:{its}\:{centre}\:{and}\:{radius}\:{if}\:{it}\:{touches}\:{the}\:{line}\:{y}+{x}=\mathrm{4}. \\ $$ Answered by john santu last updated on 01/Oct/20…
Question Number 181619 by mr W last updated on 27/Nov/22 Commented by mr W last updated on 27/Nov/22 $${a}\:{goat}\:{is}\:{connected}\:{through}\:{a}\:{ring}\:{with} \\ $$$${a}\:{rope}\:{of}\:\mathrm{30}\:{m}\:{length}\:{whose}\:{ends}\:{are} \\ $$$${fixed}\:{at}\:{two}\:{points}\:{with}\:{a}\:{distance}\:{of} \\ $$$$\mathrm{20}\:{m}\:{as}\:{shown}.\:{a}\:{gate}\:{at}\:{point}\:{C}\:{on}…