Question Number 49696 by ajfour last updated on 09/Dec/18 Commented by ajfour last updated on 09/Dec/18 $${Find}\:{parameters}\:{of}\:{ellipse}\:{within} \\ $$$${the}\:{box}\:{and}\:{touching}\:{all}\:{its}\:{six} \\ $$$${faces}\:{at}\:{A},\:{B},\:{C},\:{D},\:{E},\:{and}\:{F}\:\:{and} \\ $$$$\left({may}\:{be}\:{for}\:{uniqueness}\right)\:{of} \\ $$$${maximum}\:{area}.…
Question Number 180756 by mr W last updated on 16/Nov/22 Commented by mr W last updated on 17/Nov/22 $${the}\:{areas}\:{of}\:{three}\:{of}\:{the}\:{six}\:{squares} \\ $$$${are}\:{given}.\:{find}\:{the}\:{area}\:{of}\:{the}\:{shaded} \\ $$$${triangle}\:{and}\:{the}\:{areas}\:{of}\:{other}\:{three} \\ $$$${squares}.…
Question Number 115166 by I want to learn more last updated on 24/Sep/20 Answered by 1549442205PVT last updated on 24/Sep/20 $$\mathrm{77}° \\ $$ Commented by…
Question Number 180623 by cortano1 last updated on 14/Nov/22 Answered by HeferH last updated on 14/Nov/22 $$\left({R}\:+\:{r}\right)^{\mathrm{2}} =\:{r}^{\mathrm{2}} \:+\:\mathrm{4}{r}^{\mathrm{2}} \\ $$$$\:\frac{\mathrm{2}{r}}{{R}}\:=\:\frac{\mathrm{1}\:+\:\sqrt{\mathrm{3}}}{\mathrm{2}} \\ $$$$\: \\ $$…
Question Number 180615 by cherokeesay last updated on 14/Nov/22 Answered by Acem last updated on 14/Nov/22 Commented by cherokeesay last updated on 14/Nov/22 $${thank}\:{you}\:{sir}. \\…
Question Number 49536 by behi83417@gmail.com last updated on 07/Dec/18 Commented by behi83417@gmail.com last updated on 07/Dec/18 $$\bigtriangleup\:{and}\bigtriangleup\:{are}\:{equilateral}\:{triangles}\:{with} \\ $$$${parallel}\:{sides}\:{and}\:\boldsymbol{\mathrm{PM}},{is}\:{the}\:{same}\:{for} \\ $$$${all}\:{sides}.{if}:{area}\left(\bigtriangleup\right)=\mathrm{32}\:{and}\:{area}\left(\bigtriangleup\right)=\mathrm{6}, \\ $$$${then}:{valve}\:{of}\::\boldsymbol{\mathrm{PM}}=? \\ $$…
Question Number 49530 by behi83417@gmail.com last updated on 07/Dec/18 Commented by behi83417@gmail.com last updated on 07/Dec/18 $$\bigtriangleup\:{and}\:\bigtriangleup\:{are}\:{equilateral}\:{triangles}. \\ $$$${AB}=\mathrm{4},{EG}=\mathrm{2}\sqrt{\mathrm{2}}\:\:\:\left[{or}:{AB}=\mathrm{6},{EG}=\mathrm{2}\sqrt{\mathrm{6}}\right] \\ $$$$\Rightarrow\:\:\:\:\:{AE}=?\:\:\:\:,\:\:\:\:\:\measuredangle{AEI}=? \\ $$ Commented by…
Question Number 180582 by HeferH last updated on 14/Nov/22 Answered by mr W last updated on 14/Nov/22 Commented by mr W last updated on 14/Nov/22…
Question Number 180547 by mnjuly1970 last updated on 13/Nov/22 Answered by mr W last updated on 13/Nov/22 Commented by mr W last updated on 13/Nov/22…
Question Number 180510 by cherokeesay last updated on 13/Nov/22 Commented by JDamian last updated on 13/Nov/22 Great roundabout expression for "yellow rectangle" Answered by MJS_new last updated on 13/Nov/22 $$\left(\frac{{a}}{\mathrm{2}}\right)^{\mathrm{2}}…