Category: Geometry

Question Number 116466 by mr W last updated on 04/Oct/20 Commented by mr W last updated on 04/Oct/20 $$R=radiusofbigcircles$$$$r=radiusofsmallcircles$$$$let\lambda =\frac{r}{R}$$$$\mathrm{cos}\:\alpha=\frac{{R}}{{R}+{r}}=\frac{\mathrm{1}}{\mathrm{1}+\lambda}…

Question Number 181987 by Acem last updated on 03/Dec/22 Answered by Frix last updated on 03/Dec/22 $$\frac{\sin 45°}{BC}=\frac{\sin 105°}{AC}=\frac{\sin 30°}{AB})$$$$\Rightarrow \frac{BC}{AC}=\sqrt{3}-1$$$$AC+BC=14{\mathrm{it}}^{\prime }\mathrm{s}\mathrm{easy}\mathrm{to}\mathrm{get}$$$$AC=\frac{14\sqrt{3}}{3}\wedge BC=\frac{14(3-\sqrt{3})}{3}\Rightarrow AB=\frac{7\sqrt{2}(3-\sqrt{3})}{3}$$…

Question Number 116413 by soumyasaha last updated on 03/Oct/20 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 181918 by HeferH last updated on 02/Dec/22 Answered by Acem last updated on 02/Dec/22 Commented by Acem last updated on 02/Dec/22 $${Sir}\:{HeferH},\:{share}\:{with}\:{me}\:{to}\:{find}\:{x}\:{cause} \…

Question Number 181869 by mnjuly1970 last updated on 01/Dec/22 Commented by mr W last updated on 01/Dec/22 $$seeQ180582$$ Terms of Service Privacy Policy…