Question Number 222176 by cherokeesay last updated on 19/Jun/25 Answered by mr W last updated on 19/Jun/25 $$\angle{B}=\beta \\ $$$$\angle{A}=\mathrm{2}\beta \\ $$$$\angle{C}=\pi−\mathrm{3}\beta \\ $$$$\frac{{a}}{\mathrm{sin}\:\mathrm{2}\beta}=\frac{{c}}{\mathrm{sin}\:\mathrm{3}\beta}=\frac{\mathrm{25}}{\mathrm{sin}\:\beta} \\…
Question Number 222062 by ajfour last updated on 16/Jun/25 Answered by fantastic last updated on 16/Jun/25 Commented by fantastic last updated on 16/Jun/25 $${RQ}=\sqrt{{a}^{\mathrm{2}} +{a}^{\mathrm{2}}…
Question Number 221958 by ajfour last updated on 13/Jun/25 Commented by mr W last updated on 14/Jun/25 $${a}\:{may}\:{not}\:{be}\:{independent}\:{from}\:{b},\:{c}. \\ $$ Commented by ajfour last updated…
Question Number 221907 by alvan545 last updated on 12/Jun/25 Answered by fantastic last updated on 12/Jun/25 Commented by fantastic last updated on 12/Jun/25 $${CD}^{\mathrm{2}} ={CN}×{CF}…
Question Number 221815 by alvan545 last updated on 11/Jun/25 Answered by mr W last updated on 11/Jun/25 $${say}\:{AC}={c} \\ $$$${BC}^{\mathrm{2}} ={CD}^{\mathrm{2}} \\ $$$${a}^{\mathrm{2}} +{c}^{\mathrm{2}} −\mathrm{2}{ac}\:\mathrm{cos}\:\theta={b}^{\mathrm{2}}…
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Question Number 221707 by Tawa11 last updated on 09/Jun/25 Commented by Tawa11 last updated on 09/Jun/25 In the ∆ABC |AB|=|BC|=|AC|=K, Area of the shaded ∆…
Question Number 221733 by Tawa11 last updated on 09/Jun/25 Commented by Tawa11 last updated on 09/Jun/25 $$\mathrm{Is}\:\:\mathrm{10}.\mathrm{37cm}\:\:\mathrm{correct}? \\ $$ Commented by ajfour last updated on…
Question Number 221637 by ASAD7391 last updated on 08/Jun/25 Answered by fantastic last updated on 09/Jun/25 $${let}\:\angle{A}=\theta\:\therefore\angle{B}=\mathrm{2}\theta\: \\ $$$${but}\:\angle{A}+\angle{B}+\angle{C}=\mathrm{180}^{\mathrm{0}} \\ $$$${or}\:\theta+\mathrm{2}\theta=\mathrm{180}^{\mathrm{0}} −\mathrm{90}^{\mathrm{0}} =\mathrm{90}^{\mathrm{0}} \\ $$$${or}\:\theta=\frac{\mathrm{90}^{\mathrm{0}}…