Question Number 178967 by Tawa11 last updated on 23/Oct/22 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{greatest}\:\mathrm{coefficient}\:\mathrm{in}\:\mathrm{expansion}\:\mathrm{of}:\:\:\:\left(\mathrm{3x}\:\:\:−\:\:\:\mathrm{2}\right)^{\mathrm{25}} \\ $$ Answered by mr W last updated on 23/Oct/22 $${a}_{{n}} ={C}_{{n}} ^{\mathrm{25}} \mathrm{3}^{{n}} \left(−\mathrm{2}\right)^{\mathrm{25}−{n}}…
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Question Number 47883 by behi83417@gmail.com last updated on 16/Nov/18 Commented by behi83417@gmail.com last updated on 16/Nov/18 $$\measuredangle{A}=\mathrm{90}^{\bullet} ,{colored}\:{shapes}\:{such}:{ACHG}, \\ $$$${are}\:{squares}\:{and}\:{points}:{L},…{are} \\ $$$${square}\:{centers}. \\ $$$$\mathrm{1}.{show}\:{that}:\:{AF}\:{is}\:{the}\:{angular}\: \\…
Question Number 47881 by behi83417@gmail.com last updated on 16/Nov/18 Commented by behi83417@gmail.com last updated on 16/Nov/18 $$\measuredangle{A}=\mathrm{90}^{\bullet} ,{AB}=\mathrm{6},{AC}=\mathrm{8},{AD}={AE}=\mathrm{3}.\mathrm{6} \\ $$$$\rightarrow\measuredangle{BFC}=?,{areaB}\overset{\bigtriangleup} {{F}C}=? \\ $$ Terms of…
Question Number 178947 by HeferH last updated on 23/Oct/22 Answered by mr W last updated on 23/Oct/22 Commented by mr W last updated on 23/Oct/22…
Question Number 47824 by ajfour last updated on 15/Nov/18 Commented by ajfour last updated on 15/Nov/18 $${Find}\:{the}\:{equation}\:{of}\:{the}\:{shadow} \\ $$$${curve}\:{of}\:{a}\:{sphere}\:{of}\:{radius}\:{R} \\ $$$${mounted}\:{on}\:{a}\:{pole}\:{of}\:{height}\:{h}. \\ $$ Commented by…
Question Number 178884 by mr W last updated on 22/Oct/22 Commented by mr W last updated on 22/Oct/22 $${a}\:{goat}\:{is}\:{tied}\:{at}\:{a}\:{point}\:{on}\:{the}\:{foot}\:{of} \\ $$$${a}\:{hill}\:{which}\:{has}\:{the}\:{shape}\:{of}\:{a}\:{sphere}\: \\ $$$${with}\:{radius}\:\mathrm{60}{m}\:{and}\:\:{height}\:\mathrm{20}{m}\:{as}\: \\ $$$${shown}.\:{the}\:{length}\:{of}\:{the}\:{rope}\:{is}\:\mathrm{20}{m}.…
Question Number 47788 by behi83417@gmail.com last updated on 14/Nov/18 Commented by behi83417@gmail.com last updated on 14/Nov/18 $${ABCD}:{square}. \\ $$$$\measuredangle{AEC}=\theta,\measuredangle{BED}=\varphi. \\ $$$${show}\:{that}:\:\:\:\:\frac{{S}_{{B}\overset{\blacktriangle} {{E}D}} }{{S}_{{A}\overset{\blacktriangle} {{E}C}} }=\frac{{tg}\varphi}{{tg}\theta}…
Question Number 47779 by ajfour last updated on 14/Nov/18 Commented by mr W last updated on 14/Nov/18 $${best}\:{illustration}\:{for}\:{this}\:{question}\:{sir}! \\ $$ Terms of Service Privacy Policy…
Question Number 47775 by behi83417@gmail.com last updated on 14/Nov/18 Commented by behi83417@gmail.com last updated on 14/Nov/18 $$\boldsymbol{\mathrm{ABC}}:{equilateral}. \\ $$$${distance}\:{of}\:\boldsymbol{\mathrm{D}}{from}:\boldsymbol{\mathrm{F}},\boldsymbol{\mathrm{E}},\boldsymbol{\mathrm{C}}=\mathrm{2},\mathrm{3},\mathrm{6} \\ $$$$\left({respectively}\right) \\ $$$$\rightarrow…..\boldsymbol{\mathrm{AB}}=? \\ $$…