Question Number 181494 by Acem last updated on 26/Nov/22 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 181485 by mr W last updated on 25/Nov/22 $${two}\:{medians}\:{of}\:{a}\:{triange}\:{are}\:\mathrm{3}\:{and} \\ $$$$\mathrm{4}\:{cm}\:{respectively}.\:{find}\:{the}\:{maximum} \\ $$$${area}\:{of}\:{the}\:{triangle}. \\ $$ Answered by Acem last updated on 26/Nov/22 Commented…
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Question Number 181437 by mnjuly1970 last updated on 25/Nov/22 Answered by MJS_new last updated on 25/Nov/22 $$\mathrm{let}\:{d},\:\sqrt{{b}^{\mathrm{2}} +{d}^{\mathrm{2}} }\:\mathrm{the}\:\mathrm{other}\:\mathrm{sides}\:\mathrm{of}\:\mathrm{the}\:\mathrm{rectangular} \\ $$$$\mathrm{triangle} \\ $$$${p}+{q}=\sqrt{{b}^{\mathrm{2}} +{d}^{\mathrm{2}} };\:{h}^{\mathrm{2}}…
Question Number 181432 by mr W last updated on 25/Nov/22 Commented by mr W last updated on 25/Nov/22 $${find}\:{the}\:{area}\:{of}\:{circle}. \\ $$ Commented by universe last…
Question Number 50352 by mr W last updated on 16/Dec/18 $${The}\:{distances}\:{from}\:{a}\:{point}\:{to}\:{the}\:{sides} \\ $$$${of}\:{a}\:{triangle}\:{are}\:{p},{q},{r}.\:{Find}\:{the}\: \\ $$$${maximum}\:\left({or}\:{minimum}\right)\:{area}\:{of}\:{the} \\ $$$${triangle},\:{if}\:{it}\:{exists}. \\ $$$${Assume}\:{r}\leqslant{q}\leqslant{p}. \\ $$ Commented by ajfour last…
Question Number 181329 by manxsol last updated on 24/Nov/22 Answered by som(math1967) last updated on 24/Nov/22 Commented by som(math1967) last updated on 24/Nov/22 $$\bigtriangleup{AOD}\sim\bigtriangleup{COB} \\…
Question Number 181327 by HeferH last updated on 24/Nov/22 Answered by a.lgnaoui last updated on 24/Nov/22 $$\measuredangle{BED}=\mathrm{45}° \\ $$ Answered by a.lgnaoui last updated on…
Question Number 181232 by mr W last updated on 23/Nov/22 Commented by mr W last updated on 23/Nov/22 $${a}\:{train}\:{drives}\:{from}\:{A}\:{in}\:{direction}\:{to} \\ $$$${D}\:{with}\:{speed}\:\mathrm{160}\:{km}/{h}.\:{at}\:{the}\:{same} \\ $$$${time}\:{a}\:{car}\:{drives}\:{from}\:{B}\:{in}\:{direction} \\ $$$${to}\:{E}\:{with}\:{speed}\:\mathrm{100}\:{km}/{h}.…
Question Number 181201 by HeferH last updated on 22/Nov/22 Answered by ARUNG_Brandon_MBU last updated on 23/Nov/22 $$\mathrm{tan}\theta=\frac{\mathrm{3}}{\mathrm{4}} \\ $$$$\mathrm{tan2}\theta=\frac{\frac{\mathrm{3}}{\mathrm{4}}+\frac{\mathrm{3}}{\mathrm{4}}}{\mathrm{1}−\frac{\mathrm{3}}{\mathrm{4}}\centerdot\frac{\mathrm{3}}{\mathrm{4}}}=\frac{\mathrm{24}}{\mathrm{7}}=\frac{{AC}}{{AE}}=\frac{{AC}}{\mathrm{4}} \\ $$$$\Rightarrow{AC}=\frac{\mathrm{96}}{\mathrm{7}} \\ $$$$\mathrm{area}\left({ABC}\right)=\frac{\mathrm{1}}{\mathrm{2}}×{AB}×{AC} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{\mathrm{1}}{\mathrm{2}}×\mathrm{9}×\frac{\mathrm{96}}{\mathrm{7}}=\frac{\mathrm{432}}{\mathrm{7}}…