Geometry – Page 122

Question-181812

Tinku Tara June 4, 2023 Geometry 0 Comments

Question Number 181812 by HeferH last updated on 01/Dec/22 Answered by mr W last updated on 01/Dec/22 $\sin 30 ° = \frac{\sin (2 α + 30 °)}{2 \cos α}$ $\sin (2 α + 30 °) = \cos α = \sin (90 ° - α)$ $2 α + 30 ° = 90 ° - α \Rightarrow α = 20 °$ $${or} \…

one-side-of-a-triangle-is-20-cm-the-other-two-sides-are-in-ratio-1-3-1-what-is-the-maximum-area-of-the-triangle-if-exists-2-what-is-the-maximun-perimeter-of-the-triangle-if-exists-

Tinku Tara June 4, 2023 Geometry 0 Comments

Question Number 181783 by mr W last updated on 30/Nov/22 $o n e s i d e o f a t r i a n g l e i s 20 c m . t h e$ $o t h e r t w o s i d e s a r e i n r a t i o 1 : 3 .$ $1) w h a t i s t h e m a x i m u m a r e a o f t h e$ $t r i a n g l e, i f e x i s t s ?$ $2) w h a t i s t h e m a x i m u n p e r i m e t e r$ $o f t h e t r i a n g l e, i f e x i s t s ?$ Answered by…

Question-181766

Tinku Tara June 4, 2023 Geometry 0 Comments

Question Number 181766 by HeferH last updated on 30/Nov/22 Answered by som(math1967) last updated on 30/Nov/22 $l e t r a d i u s o f i n n e r c i r c l e = r$ $\frac{C I}{r} = c o s e c 20 \Rightarrow C I = r c o s e c 20$ $c = r c o t 30 + r c o t 40$ $= r (\frac{c o s 30 s i n 40 + c o s 40 s i n 30}{s i n 30 s i n 40})$ $$={r}\left(\frac{\mathrm{2}{sin}\mathrm{70}}{\mathrm{2}{sin}\mathrm{20}{cos}\mathrm{20}}\right)…

Question-181759

Tinku Tara June 4, 2023 Geometry 0 Comments

Question Number 181759 by mr W last updated on 29/Nov/22 Commented by mr W last updated on 30/Nov/22 $B C = a$ $\frac{A B}{A C} = k = c o n s t a n t$ $w h a t i s t h e l o c u s o f p o i n t A ?$ …

Find-the-maximum-area-of-a-triangle-inscribed-in-an-ellipse-with-parameters-a-and-b-

Tinku Tara June 4, 2023 Geometry 0 Comments

Question Number 50674 by mr W last updated on 18/Dec/18 $F i n d t h e m a x i m u m a r e a o f a t r i a n g l e$ $i n s c r i b e d i n a n e l l i p s e w i t h p a r a m e t e r s$ $a a n d b .$ Commented by ajfour last updated on 18/Dec/18 Commented…

Question-181736

Tinku Tara June 4, 2023 Geometry 0 Comments

Question Number 181736 by mnjuly1970 last updated on 29/Nov/22 Answered by universe last updated on 30/Nov/22 $s e e q u e s t i o n 172437$ Terms of Service Privacy Policy Contact:…

Question-181710

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Question Number 181710 by Ari last updated on 28/Nov/22 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question-181711

Tinku Tara June 4, 2023 Geometry 0 Comments

Question Number 181711 by Ari last updated on 28/Nov/22 Commented by mr W last updated on 29/Nov/22 $\frac{9}{53 + 9} \times 48 = \frac{216}{31}$ $\frac{9}{53 - 9} \times 48 = \frac{108}{11}$ $\frac{1}{2} (\frac{216}{31} + \frac{108}{11}) = \frac{2862}{341} \approx 8.4 < 16$ $$\Rightarrow{triangle}\:{with}\:{height}\:\mathrm{16}\:{impossile}! \…

Question-181673

Tinku Tara June 4, 2023 Geometry 0 Comments

Question Number 181673 by cherokeesay last updated on 28/Nov/22 Answered by HeferH last updated on 28/Nov/22 $A = \frac{(r_{1} + r_{2}) B D}{2}$ $B D = 5 - (\frac{16}{5} + 1) = \frac{25 - 21}{5} = \frac{4}{5}$ $A = \frac{1}{2} (2 + \frac{12}{5}) \frac{4}{5} = \frac{44}{25} u^{2}$ …

Question-181651

Tinku Tara June 4, 2023 Geometry 0 Comments

Question Number 181651 by mr W last updated on 28/Nov/22 Commented by Acem last updated on 05/Dec/22 $D i d y o u b o t h b e l i e v e h i m w i t h a l l y o u r m i n d s ?$ $H e j u s t t r y i n g t o m a k e y o u f e e l r e m o r s e a n d$ $g i v e t h e g o a t e t e r n a l r e s t a n d t h e n i n v i t e h i m$ $$\:{to}\:{a}\:{barbecue} \…

Category: Geometry