Question Number 115642 by 24224 Opiyo Kamuki last updated on 27/Sep/20 $${A}\:{vertical}\:{post}\:{of}\:{height}\:{h}\:{m}\:{rises}\:{from}\:{a}\:{plane}\:{which}\: \\ $$$${slopes}\:{down}\:{towards}\:{the}\:{South}\:{at}\:{an}\:{angle} \\ $$$$\alpha\:{to}\:{the}\:{horizontal}.\:{Prove}\:{that}\:{the}\:{length} \\ $$$${of}\:{its}\:{shadow}\:{when}\:{the}\:{sun}\:{is}\:\boldsymbol{{S}\theta{W}}\:\: \\ $$$${at}\:{an}\:{elevation}\:\beta\:{is} \\ $$$$ \\ $$$$\frac{{h}\sqrt{\left(\mathrm{1}+{tan}^{\mathrm{2}} \alpha\:{cos}^{\mathrm{2}}…
Question Number 181151 by mr W last updated on 22/Nov/22 Answered by SEKRET last updated on 22/Nov/22 $$\:\sqrt{\mathrm{2}} \\ $$ Answered by SEKRET last updated…
Question Number 181128 by Acem last updated on 21/Nov/22 Commented by Acem last updated on 21/Nov/22 $$\:{Find}\:{the}\:{length}\:{of}\:{the}\:{crease}\:{L}\left({w},\:\theta\right) \\ $$ Commented by Acem last updated on…
Question Number 181125 by depressiveshrek last updated on 21/Nov/22 $${Let}\:{the}\:{acute}\:{triangle}\:\Delta{ABC}\:\:{have} \\ $$$${an}\:{outer}\:{circumscribed}\:{circle}, \\ $$$${whose}\:{tangents}\:{at}\:{the}\:{points}\:{B}\:{and}\:{C} \\ $$$${intersect}\:{at}\:{point}\:{P}.\:{Let}\:{D}\:{and}\:{E}\:{be} \\ $$$${the}\:{projections}\:{of}\:{perpendicular} \\ $$$${lines}\:{from}\:{point}\:{P}\:{on}\:{AC}\:{and}\:{AB}. \\ $$$${Prove}\:{that}\:{the}\:{interdection}\:{point}\:{of} \\ $$$${the}\:{heights}\:{of}\:\Delta{ADE}\:{is}\:{the}\:{midpoint} \\…
Question Number 181085 by mr W last updated on 21/Nov/22 Commented by mr W last updated on 21/Nov/22 $${find}\:{the}\:{diameter}\:{of}\:{semicircle}. \\ $$ Commented by HeferH last…
Question Number 181070 by mr W last updated on 21/Nov/22 Commented by mr W last updated on 21/Nov/22 $$\left[{Q}\mathrm{181055}\:{modified}\right] \\ $$$${find}\:{the}\:{area}\:{of}\:{trapazoid}\:{ABCD}. \\ $$ Commented by…
Question Number 49987 by ajfour last updated on 12/Dec/18 Commented by ajfour last updated on 12/Dec/18 $${a}\:\neq\:{b}\:,\:{find}\:\boldsymbol{{c}}\:\:{in}\:{terms}\:{of}\:{a}\:{and}\:{b}. \\ $$ Commented by MJS last updated on…
Question Number 49984 by behi83417@gmail.com last updated on 12/Dec/18 Commented by behi83417@gmail.com last updated on 12/Dec/18 $${A}\overset{\bigtriangleup} {{B}C},{equilateral}.{AB}={a},{A}\overset{} {{C}E}=\alpha. \\ $$$${find}:{AD},{BD},{in}\:{terms}\:{of}\:{a}\:{and}\:\:\alpha. \\ $$ Answered by…
Question Number 181051 by mr W last updated on 20/Nov/22 Answered by a.lgnaoui last updated on 21/Nov/22 $${cote}\:{du}\:{carre}\:{bleu}\:\left[{CD}\right]={b}\:{comme}\:{il} \\ $$$${apparait}\:{dans}\:\left({image}\right){est} \\ $$$${CD}:{prolongement}\:{de}\left[\:{AC}\right]\left({AC}\right) \\ $$$$\left[{CD}\right]=\mathrm{2}×{AC} \\…
Question Number 181055 by Acem last updated on 21/Nov/22 Commented by Acem last updated on 21/Nov/22 $$\ast\:{DABC} \\ $$$${Please},\:{the}\:{comments}\:{section}\:{is}\:{only} \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:{for} \\ $$$$\:\:\:\:\:\boldsymbol{{inquiries}}\:\boldsymbol{{and}}\:\boldsymbol{{clarifications}} \\ $$$$…