Question Number 178299 by HeferH last updated on 14/Oct/22 Answered by mr W last updated on 15/Oct/22 Commented by mr W last updated on 15/Oct/22…
Question Number 47216 by ajfour last updated on 06/Nov/18 Commented by ajfour last updated on 06/Nov/18 $${Q}.\mathrm{47195}\:\: \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 47217 by ajfour last updated on 06/Nov/18 Commented by ajfour last updated on 06/Nov/18 $${Q}.\mathrm{47195}\:{paper}\:{pyramid}\:{question} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 47195 by MrW3 last updated on 06/Nov/18 $${Find}\:{the}\:{volume}\:{of}\:{the}\:{pyramid}\:{which} \\ $$$${is}\:{folded}\:{from}\:{a}\:{trangular}\:{paper}\:{with} \\ $$$${sides}\:\boldsymbol{{a}},\:\boldsymbol{{b}}\:{and}\:\boldsymbol{{c}}. \\ $$ Answered by MJS last updated on 06/Nov/18 $$\mathrm{in}\:\mathrm{this}\:\mathrm{case}\:\mathrm{it}'\mathrm{s}\:\mathrm{easy}\:\mathrm{to}\:\mathrm{use}\:\mathrm{Euler}'\mathrm{s}\:\mathrm{formula} \\…
Question Number 47135 by Tawa1 last updated on 05/Nov/18 Commented by Meritguide1234 last updated on 05/Nov/18 $${ans}\:\left\{\mathrm{2},\mathrm{1}\right\}\:{and}\:\left\{\frac{\mathrm{2}}{\mathrm{5}},−\frac{\mathrm{1}}{\mathrm{5}}\right\} \\ $$ Commented by behi83417@gmail.com last updated on…
Question Number 47113 by MrW3 last updated on 04/Nov/18 Commented by MrW3 last updated on 04/Nov/18 $${Find}\:{the}\:{volume}\:{of}\:{the}\:{triangular} \\ $$$${pyramid}\:{with}\:{given}\:{edge}\:{lengthes}. \\ $$ Commented by MJS last…
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Question Number 112500 by I want to learn more last updated on 08/Sep/20 Answered by 1549442205PVT last updated on 08/Sep/20 $$\mathrm{The}\:\mathrm{area}\:\mathrm{of}\:\mathrm{smallesr}\:\mathrm{yellow}\:\:\mathrm{part} \\ $$$$\mathrm{equal}\:\mathrm{to}\:\frac{\mathrm{1}}{\mathrm{4}}.\frac{\mathrm{1}}{\mathrm{3}}\mathrm{S}\left(\mathrm{S}=\mathrm{6}\right)=\frac{\mathrm{1}}{\mathrm{2}} \\ $$$$\mathrm{The}\:\mathrm{area}\:\mathrm{of}\:\mathrm{yellow}\:\mathrm{middle}\:\mathrm{part}\:\mathrm{equal}…
Question Number 178001 by Tawa11 last updated on 11/Oct/22 Commented by Tawa11 last updated on 11/Oct/22 $$\left(\mathrm{b}\right)\:\:\:\mathrm{The}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{shaded}\:\mathrm{part}. \\ $$ Answered by aleks041103 last updated on…
Question Number 46919 by behi83417@gmail.com last updated on 02/Nov/18 Commented by ajfour last updated on 02/Nov/18 Commented by ajfour last updated on 02/Nov/18 $${let}\:{CF}\:={h}\:;\:\:{FM}={FB}\:=\:\sqrt{\mathrm{4}−{h}^{\mathrm{2}} }…