Menu Close

Category: Geometry

Question-116800

Question Number 116800 by mr W last updated on 06/Oct/20 Answered by bobhans last updated on 07/Oct/20 sin8xsin4x=sin5xsin3x;2sin4x.cos4xsin4x=sin5xsin3x2sin3x.cos4x=sin5xsin7x+sin(x)=sin5x$$\Rightarrow\mathrm{sin}\:\mathrm{7x}−\mathrm{sin}\:\mathrm{5x}\:+\mathrm{sin}\:\left(−\mathrm{x}\right)=\mathrm{0} \

Question-51245

Question Number 51245 by Tawa1 last updated on 25/Dec/18 Answered by afachri last updated on 25/Dec/18 (2)toevaluateHReactionwithbondenergy:HReaction=HrHp$$\bigtriangleup{H}_{\mathrm{p}} \:;\:\left(\:\mathrm{N}−\mathrm{N}\right)\:+\:\mathrm{4}\left(\mathrm{N}−\mathrm{H}\right)\:=\:\left(+\mathrm{167}\right)\:\:+\:\:\mathrm{4}\left(\mathrm{385}.\mathrm{9}\right)…

Question-182292

Question Number 182292 by HeferH last updated on 07/Dec/22 Answered by Acem last updated on 07/Dec/22 x=90°Idouptfromthecommonsideandthe2equalsbasessin40sinx=sin20sin120x2cos20sinx=1sin120x2cos20(32cosx+12sinx)=sinx$$\:\sqrt{\mathrm{3}}\:\mathrm{cos}\:\mathrm{20}\:\mathrm{cos}\:{x}=\:\mathrm{sin}\:{x}\:\left(\mathrm{1}−\:\mathrm{cos}\:\mathrm{20}\right)…