Question Number 177353 by HeferH last updated on 04/Oct/22 Commented by HeferH last updated on 04/Oct/22 $$\left.:\right) \\ $$ Answered by BaliramKumar last updated on…
Question Number 177205 by HeferH last updated on 02/Oct/22 Answered by mr W last updated on 02/Oct/22 $$\angle{CAD}=\mathrm{180}−\mathrm{120}−\mathrm{3}{x}=\mathrm{60}−\mathrm{3}{x} \\ $$$$\angle{CDB}=\mathrm{180}−\mathrm{3}{x} \\ $$$${applying}\:{law}\:{of}\:{sines}: \\ $$$$\frac{\mathrm{sin}\:\left(\mathrm{60}−\mathrm{3}{x}\right)}{{CD}}=\frac{\mathrm{sin}\:\mathrm{120}}{{AD}}\:\:\:…\left({i}\right) \\…
Question Number 46073 by ajfour last updated on 20/Oct/18 Commented by ajfour last updated on 20/Oct/18 $${Determine}\:{coordinates}\:{of}\:{A}; \\ $$$$\:\:\:{b}\:>\:{c}\:.\:{P}\:{is}\:{contact}\:{point}\:{of}\:{side} \\ $$$${AB}\:{of}\:\bigtriangleup{ABC}\:{with}\:{upper}\:{rim}\:{of} \\ $$$${cylinder}\:\left({height}\:{H},\:{radius}\:{R}\right). \\ $$…
Question Number 177128 by cortano1 last updated on 01/Oct/22 Commented by cortano1 last updated on 01/Oct/22 $$\mathrm{all}\:\mathrm{angles}\:=\mathrm{120}°\:.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{perimeter} \\ $$ Answered by mr W last updated…
Question Number 111539 by Aina Samuel Temidayo last updated on 04/Sep/20 $$\mathrm{In}\:\mathrm{a}\:\mathrm{trapezoid}\:\mathrm{ABCD},\:\mathrm{sides}\:\mathrm{AB}\:\mathrm{and} \\ $$$$\mathrm{CD}\:\mathrm{are}\:\mathrm{parallel}\:\mathrm{and}\:\mathrm{side}\:\mathrm{BC}=\mathrm{CD}=\sqrt{\mathrm{5}}. \\ $$$$\mathrm{If}\:\mathrm{D}\hat {\mathrm{C}B}\:=\mathrm{120}°\:\mathrm{and}\:\mathrm{B}\hat {\mathrm{A}D}=\mathrm{60}°.\:\mathrm{Find} \\ $$$$\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{ABCD}. \\ $$ Answered by 1549442205PVT…
Question Number 45980 by ajfour last updated on 19/Oct/18 Commented by ajfour last updated on 19/Oct/18 $${Determine}\:{sides}\:{of}\:\bigtriangleup,\: \\ $$$$\boldsymbol{{a}},\:{and}\:\boldsymbol{{b}}\:=\:\boldsymbol{{c}}\:,\:{in}\:{terms}\:{of}\:\boldsymbol{{R}},\:\boldsymbol{{r}},\:\boldsymbol{{d}}. \\ $$ Answered by MrW3 last…
Question Number 111497 by bemath last updated on 04/Sep/20 Commented by kaivan.ahmadi last updated on 04/Sep/20 $${let}\:{t}={x}_{\mathrm{1}} ^{\mathrm{3}} +\mathrm{6}{x}_{\mathrm{1}} ^{\mathrm{2}} −\mathrm{30}{x}_{\mathrm{1}} +{x}_{\mathrm{1}} ^{\mathrm{2}} {x}_{\mathrm{2}} −\mathrm{5}{x}_{\mathrm{1}}…
Question Number 177031 by HeferH last updated on 29/Sep/22 Answered by mr W last updated on 30/Sep/22 Commented by mr W last updated on 30/Sep/22…
Question Number 111477 by Aina Samuel Temidayo last updated on 03/Sep/20 $$\mathrm{Triangle}\:\mathrm{ABC}\:\mathrm{has}\:\mathrm{AB}=\mathrm{2}\centerdot\mathrm{AC}.\:\mathrm{Let} \\ $$$$\mathrm{D}\:\mathrm{and}\:\mathrm{E}\:\mathrm{be}\:\mathrm{on}\:\mathrm{AB}\:\mathrm{and}\:\mathrm{BC} \\ $$$$\mathrm{respectively}\:\mathrm{such}\:\mathrm{that}\:\angle\mathrm{BAE} \\ $$$$=\angle\mathrm{ACD}.\:\mathrm{Let}\:\mathrm{F}\:\mathrm{be}\:\mathrm{the}\:\mathrm{intersections}\:\mathrm{of} \\ $$$$\mathrm{segments}\:\mathrm{AE}\:\mathrm{and}\:\mathrm{CD},\:\mathrm{and}\:\mathrm{suppose} \\ $$$$\mathrm{that}\:\bigtriangleup\mathrm{CFE}\:\mathrm{is}\:\mathrm{equilateral}.\:\mathrm{What}\:\mathrm{is} \\ $$$$\angle\mathrm{ACB}? \\…
Question Number 177013 by mr W last updated on 29/Sep/22 Commented by mr W last updated on 29/Sep/22 $${find}\:{the}\:{area}\:{of}\:{the}\:{sector}. \\ $$ Answered by Rasheed.Sindhi last…