Category: Geometry

Question Number 47349 by behi83417@gmail.com last updated on 08/Nov/18 Answered by behi83417@gmail.com last updated on 09/Nov/18 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 47250 by Raj Singh last updated on 07/Nov/18 Answered by MJS last updated on 07/Nov/18 $$\mathrm{surface}\:\mathrm{of}\:\mathrm{cuboid} \\ $$$$\mathrm{2}×\left(\mathrm{15}×\mathrm{10}+\mathrm{15}×\mathrm{5}+\mathrm{10}×\mathrm{5}\right)=\mathrm{550} \\ $$$$\mathrm{surface}\:\mathrm{of}\:\mathrm{cylinder}\:\left(\mathrm{without}\:\mathrm{bottom\&top}\right) \\ $$$$\mathrm{2}×\mathrm{3}.\mathrm{5}\pi×\mathrm{5}=\mathrm{35}\pi \\…

Question Number 47243 by MrW3 last updated on 06/Nov/18 Answered by MJS last updated on 07/Nov/18 $$\mathrm{left}\:\mathrm{picture} \\ $$$$\frac{\mathrm{8}}{{r}}=\frac{{H}}{{R}}\:\Rightarrow\:{r}=\frac{\mathrm{8}{R}}{{H}} \\ $$$${v}_{{blue}} =\frac{\pi{R}^{\mathrm{2}} \left({H}^{\mathrm{2}} +\mathrm{8}{H}+\mathrm{64}\right)\left({H}−\mathrm{8}\right)}{\mathrm{3}{H}^{\mathrm{2}} }…

Question Number 47216 by ajfour last updated on 06/Nov/18 Commented by ajfour last updated on 06/Nov/18 $${Q}.\mathrm{47195}\:\: \\ $$ Terms of Service Privacy Policy Contact:…

Question Number 47195 by MrW3 last updated on 06/Nov/18 $${Find}\:{the}\:{volume}\:{of}\:{the}\:{pyramid}\:{which} \\ $$$${is}\:{folded}\:{from}\:{a}\:{trangular}\:{paper}\:{with} \\ $$$${sides}\:\boldsymbol{{a}},\:\boldsymbol{{b}}\:{and}\:\boldsymbol{{c}}. \\ $$ Answered by MJS last updated on 06/Nov/18 $$\mathrm{in}\:\mathrm{this}\:\mathrm{case}\:\mathrm{it}'\mathrm{s}\:\mathrm{easy}\:\mathrm{to}\:\mathrm{use}\:\mathrm{Euler}'\mathrm{s}\:\mathrm{formula} \\…