Question Number 174315 by mnjuly1970 last updated on 29/Jul/22 Answered by aleks041103 last updated on 29/Jul/22 $${if}\:{the}\:{intersection}\:{point}\:{on}\:{AB}\:{is}\:{O}, \\ $$$${let}'{s}\:{set}\:{its}\:{coordinates}\:{to}\:\left(\mathrm{0},\mathrm{0}\right) \\ $$$${then}\:{OB}\:{is}\:{the}\:{x}\:{axis}. \\ $$$${then}\:{th}\:{equation}\:{of}\:{the}\:{slanted}\:{line}\:{is}: \\ $$$${y}={x}…
Question Number 174283 by ajfour last updated on 28/Jul/22 Commented by ajfour last updated on 28/Jul/22 $${Find}\:{PQ}\:{in}\:{terms}\:{of}\:{a},{b},\theta. \\ $$ Answered by mr W last updated…
Question Number 43205 by Tawa1 last updated on 08/Sep/18 Answered by $@ty@m last updated on 08/Sep/18 $$\because\angle{SRQ}=\angle{RTS}\:\left({alternate}\:{segment}\:{theorem}\right) \\ $$$$\therefore\angle{SRQ}=\mathrm{28}^{\mathrm{o}} \\ $$$${We}\:{have} \\ $$$$\angle{VRM}+\angle{VRS}+\angle{SRQ}=\mathrm{180}^{\mathrm{o}} \\ $$$$\Rightarrow\mathrm{46}^{\mathrm{o}}…
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Question Number 43135 by MrW3 last updated on 07/Sep/18 $${Construct}\:{a}\:{triangle}\:\Delta{ABC}\:{with} \\ $$$$\angle{B}=\mathrm{50}° \\ $$$${AC}=\mathrm{6}\:{cm} \\ $$$${AB}+{BC}=\mathrm{8}\:{cm} \\ $$$$ \\ $$$${see}\:{also}\:{Q}\mathrm{42942}. \\ $$ Commented by math1967…
Question Number 174185 by nadovic last updated on 26/Jul/22 $$\mathrm{The}\:\mathrm{circle}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} −\mathrm{2}{x}−\mathrm{4}{y}−\mathrm{20}=\mathrm{0}\:\mathrm{is} \\ $$$$\mathrm{inscribed}\:\mathrm{in}\:\mathrm{a}\:\mathrm{square}.\:\mathrm{One}\:\mathrm{vertex} \\ $$$$\mathrm{of}\:\mathrm{the}\:\mathrm{square}\:\mathrm{is}\:\left(−\mathrm{4},\:\mathrm{7}\right).\:\mathrm{Find}\:\mathrm{the} \\ $$$$\mathrm{coordinates}\:\mathrm{of}\:\mathrm{the}\:\mathrm{other}\:\mathrm{vertices}. \\ $$ Answered by Cesar1994 last updated…
Question Number 108626 by I want to learn more last updated on 18/Aug/20 Answered by Aziztisffola last updated on 18/Aug/20 $$\mathrm{A}_{\frac{\mathrm{1}}{\mathrm{2}}\mathrm{circle}} =\frac{\mathrm{1}}{\mathrm{2}}\pi\left(\frac{\mathrm{a}}{\mathrm{2}}\right)^{\mathrm{2}} =\frac{\pi\mathrm{a}^{\mathrm{2}} }{\mathrm{8}} \\…
Question Number 174094 by nadovic last updated on 24/Jul/22 $$\mathrm{The}\:\mathrm{circles}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} −\mathrm{2}{ax}+\mathrm{8}{y}+\mathrm{13}=\mathrm{0} \\ $$$$\mathrm{and}\:{x}^{\mathrm{2}} +{y}^{\mathrm{2}} +\mathrm{2}{x}+\mathrm{2}{by}+\mathrm{1}=\mathrm{0}\:\mathrm{are}\: \\ $$$$\mathrm{congruent}.\:\mathrm{If}\:\mathrm{they}\:\mathrm{are}\:\mathrm{2}\sqrt{\mathrm{10}}\:\mathrm{units}\: \\ $$$$\mathrm{apart},\:\mathrm{find}\:\mathrm{the}\:\mathrm{possible}\:\mathrm{values}\:\mathrm{of} \\ $$$${a}\:\mathrm{and}\:{b}. \\ $$ Answered…
Question Number 108538 by I want to learn more last updated on 17/Aug/20 Commented by Rasheed.Sindhi last updated on 17/Aug/20 $${See}\:{Q}#\mathrm{108483} \\ $$ Terms of…
Question Number 42948 by ajfour last updated on 05/Sep/18 Commented by ajfour last updated on 05/Sep/18 $${Find}\:{coordinates}\:{of}\:{point}\:{P}\:,\:{if} \\ $$$${the}\:{coloured}\:{area}\:{is}\:{a}\:{minimum}. \\ $$ Commented by MJS last…