Question Number 175717 by ajfour last updated on 05/Sep/22 Answered by mr W last updated on 05/Sep/22 $$\left({R}−{r}\right)^{\mathrm{2}} ={r}^{\mathrm{2}} +\left(\frac{{R}}{\mathrm{2}}+{r}\right)^{\mathrm{2}} \\ $$$${r}^{\mathrm{2}} +\mathrm{3}{Rr}−\frac{\mathrm{3}{R}^{\mathrm{2}} }{\mathrm{4}}=\mathrm{0} \\…
Question Number 44636 by Raj Singh last updated on 02/Oct/18 Answered by tanmay.chaudhury50@gmail.com last updated on 02/Oct/18 $${join}\:{oB}\:{andOC} \\ $$$$\bigtriangleup{OAB}\:{and}\:{OAC}\: \\ $$$$\left.\mathrm{1}\right){OB}={OC}\:\left({radius}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\: \\…
Question Number 44621 by Tawa1 last updated on 02/Oct/18 Answered by tanmay.chaudhury50@gmail.com last updated on 02/Oct/18 $$\left.{a}\right){sector}\:{area}\:{s}=\frac{\pi{r}^{\mathrm{2}} }{\mathrm{2}\pi}×\theta=\frac{{r}^{\mathrm{2}} \theta}{\mathrm{2}} \\ $$$$\mathrm{132}=\frac{\mathrm{12}×\mathrm{12}}{\mathrm{2}}×\theta \\ $$$$\theta=\frac{\mathrm{132}×\mathrm{2}}{\mathrm{12}×\mathrm{12}}=\frac{\mathrm{11}}{\mathrm{6}} \\ $$$${l}={r}\theta…
Question Number 44548 by Tawa1 last updated on 01/Oct/18 $$\left(\mathrm{a}\right) \\ $$$$\mathrm{The}\:\mathrm{area}\:\mathrm{of}\:\mathrm{a}\:\mathrm{sector}\:\mathrm{of}\:\mathrm{a}\:\mathrm{circle}\:\mathrm{of}\:\mathrm{radius}\:\:\mathrm{12cm}\:\mathrm{is}\:\:\mathrm{132cm}^{\mathrm{2}} \:.\:\:\mathrm{If}\:\mathrm{the}\:\mathrm{sector} \\ $$$$\mathrm{is}\:\mathrm{folded}\:\mathrm{such}\:\mathrm{that}\:\mathrm{its}\:\mathrm{straight}\:\mathrm{edges}\:\mathrm{coincide}\:\mathrm{to}\:\mathrm{form}\:\mathrm{a}\:\mathrm{cone}.\:\mathrm{Find}\:\mathrm{the}\: \\ $$$$\mathrm{radius}\:\mathrm{of}\:\mathrm{the}\:\mathrm{base}\:\mathrm{of}\:\mathrm{the}\:\mathrm{cone}\:\:\:\:\left[\:\:\mathrm{Take}\:\:\:\:\pi\:\:=\:\:\frac{\mathrm{22}}{\mathrm{7}}\:\right]\:. \\ $$$$ \\ $$$$\left(\mathrm{b}\right)\:\:\: \\ $$$$\mathrm{A}\:\mathrm{circle}\:\mathrm{of}\:\mathrm{centre}\:\mathrm{O}\:\mathrm{has}\:\mathrm{radius}\:\mathrm{5cm}.\:\:\mathrm{A}\:\mathrm{chord}\:\mathrm{PQ}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circle}\:\mathrm{is}\:\mathrm{6cm}\:\mathrm{long}. \\ $$$$\mathrm{caclculate}:…
Question Number 175601 by ajfour last updated on 03/Sep/22 Answered by mr W last updated on 03/Sep/22 $${R}=\mathrm{1} \\ $$$${r}={radius}\:{of}\:{sphere} \\ $$$${if}\:{a}={b}: \\ $$$${r}\sqrt{{a}^{\mathrm{2}} +{R}^{\mathrm{2}}…
Question Number 175568 by ajfour last updated on 02/Sep/22 Commented by ajfour last updated on 02/Sep/22 $${Find}\:{the}\:{maximum}\:{inner}\:{cone} \\ $$$${volume}\:{if}\:{outer}\:{cone}\:{volume}\:{is} \\ $$$${unity}. \\ $$ Answered by…
Question Number 44497 by MrW3 last updated on 30/Sep/18 Commented by ajfour last updated on 30/Sep/18 $${the}\:{concept}\:{of}\:{greater}\:{circle} \\ $$$${route}\:{has}\:{use}\:{in}\:{this},\:{i}\:{am}\:{not} \\ $$$${able}\:{to}\:{apply}\:{it}\:{yet}.. \\ $$ Commented by…
Question Number 44479 by Necxx last updated on 29/Sep/18 Commented by Necxx last updated on 29/Sep/18 $${please}\:{help}\:{me}\:{with}\:{Q}\:\mathrm{122} \\ $$ Commented by tanmay.chaudhury50@gmail.com last updated on…
Question Number 175511 by cherokeesay last updated on 31/Aug/22 Commented by Tawa11 last updated on 15/Sep/22 $$\mathrm{Great}\:\mathrm{sir} \\ $$ Terms of Service Privacy Policy Contact:…
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