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Category: Geometry

Question-179609

Question Number 179609 by Acem last updated on 31/Oct/22 Answered by mr W last updated on 31/Oct/22 MethodIsinx2sin15°=sin(x+15°)1=sinxcos15°+cosxsin15°1sin30°+2sin215°tanx=1$$\frac{\mathrm{1}−\mathrm{cos}\:\mathrm{30}°}{\mathrm{tan}\:\gamma}=\frac{\mathrm{1}}{\mathrm{2}}…