Question Number 108483 by I want to learn more last updated on 17/Aug/20 Commented by Rasheed.Sindhi last updated on 17/Aug/20 Commented by Rasheed.Sindhi last updated…
Question Number 42942 by Raj Singh last updated on 05/Sep/18 Answered by MJS last updated on 05/Sep/18 $${BC}={a}\:\:{CA}={b}\:\:{AB}={c} \\ $$$$ \\ $$$$\mathrm{1}.\:{a}=\mathrm{6}\:\:\beta=\mathrm{50}°\:\:{b}+{c}=\mathrm{8}\:\Rightarrow\:{c}=\mathrm{8}−{b} \\ $$$$\alpha+\gamma=\mathrm{130}°\:\Rightarrow\:\gamma=\mathrm{130}°−\alpha \\…
Question Number 108474 by pticantor last updated on 17/Aug/20 $$\boldsymbol{{U}}_{\boldsymbol{{n}}} =\underset{{k}=\mathrm{0}} {\overset{\mathrm{2}{n}−\mathrm{1}} {\sum}}\frac{\mathrm{1}}{\mathrm{2}{n}+{k}}=? \\ $$$$\boldsymbol{{li}}\underset{\boldsymbol{{n}}>\infty} {\boldsymbol{{m}U}}_{{n}} =? \\ $$ Answered by Dwaipayan Shikari last updated…
Question Number 108332 by I want to learn more last updated on 16/Aug/20 Answered by mr W last updated on 16/Aug/20 Commented by mr W…
Question Number 108331 by I want to learn more last updated on 16/Aug/20 Answered by mr W last updated on 16/Aug/20 Commented by mr W…
Question Number 173825 by dragan91 last updated on 19/Jul/22 Commented by infinityaction last updated on 19/Jul/22 $${use}\:{coordinate}\:{geometry} \\ $$$$?=\:\frac{\mathrm{2}}{\mathrm{7}} \\ $$ Commented by dragan91 last…
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Question Number 173668 by mr W last updated on 16/Jul/22 Commented by mr W last updated on 16/Jul/22 $${prove}\:{that}\:{M}\:{is}\:{the}\:{midpoint}\:{of}\:{EF}. \\ $$ Answered by mr W…
Question Number 42592 by Aston last updated on 28/Aug/18 Answered by $@ty@m last updated on 28/Aug/18 $${Let}\:{PS}\:{and}\:{QE}\:{intersects}\:{at}\:{M}. \\ $$$${In}\:\bigtriangleup{PMQ}\:{and}\:\bigtriangleup{EMS}, \\ $$$$\angle{QPM}=\angle{SEM}\:\left({angle}\:{of}\:{the}\:{same}\:{segment}\right) \\ $$$${PQ}={ES}\:\left({given}\right) \\ $$$$\angle{PQM}=\angle{ESM}\:\left({angle}\:{of}\:{the}\:{same}\:{segment}\right)…