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Category: Geometry

Question-108068

Question Number 108068 by I want to learn more last updated on 14/Aug/20 Answered by Sarah85 last updated on 14/Aug/20 $$\mathrm{a}\:\mathrm{triangle}\:\mathrm{is}\:\mathrm{given}\:\mathrm{with} \\ $$$${a}=\sqrt{\mathrm{2}^{\mathrm{2}} +\mathrm{3}^{\mathrm{3}} }=\sqrt{\mathrm{13}}…

Question-42352

Question Number 42352 by Raj Singh last updated on 24/Aug/18 Answered by tanmay.chaudhury50@gmail.com last updated on 24/Aug/18 $$\angle{AOC}=\angle{BOD}=\mathrm{2}{x}\:\left({vertically}\:{opposite}\:{angle}\:{voa}\right) \\ $$$$\angle{AOB}=\angle{COD}\:\:=\mathrm{2}{y}\left({voa}\right) \\ $$$$\mathrm{2}{x}+\mathrm{2}{y}+\mathrm{2}{x}+\mathrm{2}{y}=\mathrm{360}^{{o}} \\ $$$${x}+{y}+{x}+{y}=\mathrm{180}^{{o}} \\…