Question Number 172437 by infinityaction last updated on 26/Jun/22 Answered by mr W last updated on 27/Jun/22 $${R}={radius}\:{of}\:{semicircle} \\ $$$${r}={radius}\:{of}\:{circle} \\ $$$${O}={center}\:{of}\:{semicircle} \\ $$$${AC}=\mathrm{2}{R}\:\mathrm{cos}\:\theta \\…
Question Number 41348 by behi83417@gmail.com last updated on 06/Aug/18 Commented by MJS last updated on 06/Aug/18 $$\mathrm{trapezoid}\:{ABCD} \\ $$$${a}={AB}\:\:{b}={BC}\:\:{c}={CD}\:\:{d}={DA} \\ $$$${e}={AC}\:\:{f}={BD} \\ $$$$\mathrm{which}\:\mathrm{triangles}\:\mathrm{do}\:\mathrm{you}\:\mathrm{mean}? \\ $$$$\bigtriangleup{ABC}\:\mathrm{and}\:\bigtriangleup{ABD}?…
Question Number 41347 by behi83417@gmail.com last updated on 06/Aug/18 Answered by MJS last updated on 06/Aug/18 $${m}_{{a}} =\sqrt{\frac{{b}^{\mathrm{2}} }{\mathrm{2}}+\frac{{c}^{\mathrm{2}} }{\mathrm{2}}−\frac{{a}^{\mathrm{2}} }{\mathrm{4}}} \\ $$$${m}_{{b}} =\sqrt{\frac{{a}^{\mathrm{2}} }{\mathrm{2}}+\frac{{c}^{\mathrm{2}}…
Question Number 172412 by cherokeesay last updated on 26/Jun/22 Answered by aleks041103 last updated on 26/Jun/22 $${distance}\:{from}\:{unknown}\:{center}\:{to} \\ $$$${left}\:{side}\:{is}\:{r}. \\ $$$${distance}\:{from}\:{center}\:{to}\:{top}\:{side}\:{is}\:{d}. \\ $$$$\Rightarrow\left(\mathrm{6}−{d}\right)^{\mathrm{2}} +\left(\mathrm{6}−{r}\right)^{\mathrm{2}} =\left(\mathrm{6}+{r}\right)^{\mathrm{2}}…
Question Number 172408 by infinityaction last updated on 26/Jun/22 Answered by mr W last updated on 26/Jun/22 Commented by mr W last updated on 26/Jun/22…
Question Number 41324 by ajfour last updated on 05/Aug/18 Commented by ajfour last updated on 05/Aug/18 $${How}\:{to}\:{construct}\:{the}\:{dotted}\:{blue} \\ $$$${circle}\:\:{passing}\:{through}\:{A}\:{and} \\ $$$${tangent}\:{to}\:{the}\:{shown}\:{line}\:{such} \\ $$$${that}\:{the}\:{red}\:{line}\:{is}\:{horizontal}. \\ $$$$\left({construction}\:{methods}\:{only}\:{please}\right).…
Question Number 41214 by ajfour last updated on 03/Aug/18 Commented by ajfour last updated on 03/Aug/18 $${Larger}\:{sphere}\:{is}\:{inscribed}\:{in}\:{the} \\ $$$${cube};\:{while}\:{the}\:{smaller}\:{sphere} \\ $$$${is}\:{tangent}\:{to}\:{three}\:{faces}\:{of}\:{cube} \\ $$$${and}\:{to}\:{the}\:{larger}\:{sphere}.\:{Find}\:{its} \\ $$$${radius}.…
Question Number 172284 by mnjuly1970 last updated on 25/Jun/22 Answered by mr W last updated on 25/Jun/22 $${say}\:{AC}={e},\:{BD}={f} \\ $$$$\mathrm{cos}\:{B}=\frac{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} −{e}^{\mathrm{2}} }{\mathrm{2}{ab}} \\ $$$$\mathrm{cos}\:{D}=\frac{{c}^{\mathrm{2}}…
Question Number 41203 by ajfour last updated on 03/Aug/18 Commented by ajfour last updated on 03/Aug/18 $${If}\:{AB}=\:{c}\:{is}\:{a}\:{diameter}\:{of}\:{larger} \\ $$$${circle}\:{and}\:{PQ}\:{is}\:{a}\:{diameter}\:{of} \\ $$$${the}\:{smaller}\:{circle},\:{find}\:\boldsymbol{\mathrm{x}}\:{in}\:{terms} \\ $$$${of}\:{c}\:;\:\left({geometrically}\:\right). \\ $$…
Question Number 172225 by mnjuly1970 last updated on 24/Jun/22 Answered by infinityaction last updated on 24/Jun/22 Commented by mnjuly1970 last updated on 24/Jun/22 $${thanks}\:{alot}\:{sir} \\…