Category: Geometry

Question Number 47382 by ajfour last updated on 09/Nov/18 Commented by ajfour last updated on 09/Nov/18 $$Thesidesofinclinedtriangle$$$$arep,q,andr.$$$$FindPG=h.$$$$Thesidesoftheprismboxare$$$${squares},\:{and}\:{base}\:{equilateral}.…

Question Number 47365 by Raj Singh last updated on 09/Nov/18 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 47349 by behi83417@gmail.com last updated on 08/Nov/18 Answered by behi83417@gmail.com last updated on 09/Nov/18 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 47250 by Raj Singh last updated on 07/Nov/18 Answered by MJS last updated on 07/Nov/18 $$\mathrm{surface}\mathrm{of}\mathrm{cuboid}$$$$2\times (15\times 10+15\times 5+10\times 5)=550$$$$\mathrm{surface}\mathrm{of}\mathrm{cylinder}\left(\mathrm{without}\mathrm{bottom}\mathrm{\&}\mathrm{top}\right)$$$$\mathrm{2}×\mathrm{3}.\mathrm{5}\pi×\mathrm{5}=\mathrm{35}\pi \…

Question Number 47243 by MrW3 last updated on 06/Nov/18 Answered by MJS last updated on 07/Nov/18 $$\mathrm{left}\mathrm{picture}$$$$\frac{8}{r}=\frac{H}{R}\Rightarrow r=\frac{8R}{H}$$$${v}_{{blue}} =\frac{\pi{R}^{\mathrm{2}} \left({H}^{\mathrm{2}} +\mathrm{8}{H}+\mathrm{64}\right)\left({H}−\mathrm{8}\right)}{\mathrm{3}{H}^{\mathrm{2}} }…