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Category: Geometry

Question-205892

Question Number 205892 by cortano12 last updated on 02/Apr/24 Answered by A5T last updated on 02/Apr/24 Commented by A5T last updated on 02/Apr/24 $${AC}={ytan}\left(\mathrm{3}\alpha\right);{x}={ytan}\alpha;{z}=\frac{{y}}{{cos}\alpha};{c}={y}\left({tan}\mathrm{3}\alpha−{tan}\alpha\right) \\…

Question-205861

Question Number 205861 by mr W last updated on 01/Apr/24 Answered by A5T last updated on 01/Apr/24 $$\mathrm{9}×\mathrm{9}=\left(\mathrm{2}{r}−{x}\right){x}\Rightarrow\mathrm{2}{r}−{x}=\frac{\mathrm{81}}{{x}} \\ $$$$\mathrm{21}×\mathrm{21}=\left(\mathrm{2}{r}−\mathrm{16}−{x}\right)\left(\mathrm{16}+{x}\right)=\left(\frac{\mathrm{81}}{{x}}−\mathrm{16}\right)\left(\mathrm{16}+{x}\right) \\ $$$$\Rightarrow{x}=\mathrm{2}\Rightarrow{r}=\mathrm{21}.\mathrm{25} \\ $$ Commented…

Question-205660

Question Number 205660 by marie last updated on 26/Mar/24 Answered by Skabetix last updated on 26/Mar/24 $$\mathrm{E}{xercice}\:{n}°\mathrm{4} \\ $$$$\left.\mathrm{1}\right)\:{D}'{apres}\:{le}\:{theoreme}\:{de}\:{Pythagore}\:: \\ $$$${BC}^{\mathrm{2}} ={AC}^{\mathrm{2}} +{AB}^{\mathrm{2}} \\ $$$$\Leftrightarrow{BC}^{\mathrm{2}}…