Question Number 212821 by Spillover last updated on 24/Oct/24 Answered by Spillover last updated on 25/Oct/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 212802 by Spillover last updated on 24/Oct/24 Answered by mr W last updated on 24/Oct/24 Commented by mr W last updated on 24/Oct/24…
Question Number 212801 by Spillover last updated on 24/Oct/24 Answered by som(math1967) last updated on 24/Oct/24 Commented by som(math1967) last updated on 24/Oct/24 $$\frac{{OL}}{{PL}}=\mathrm{tan}\:\mathrm{22}\frac{\mathrm{1}}{\mathrm{2}} \…
Question Number 212803 by Spillover last updated on 24/Oct/24 Answered by Spillover last updated on 24/Oct/24 Answered by Spillover last updated on 24/Oct/24 Answered by…
Question Number 212760 by Spillover last updated on 23/Oct/24 Answered by mr W last updated on 23/Oct/24 Commented by mr W last updated on 23/Oct/24…
Question Number 212761 by Spillover last updated on 23/Oct/24 Commented by mr W last updated on 23/Oct/24
Question Number 212784 by Spillover last updated on 23/Oct/24 Answered by A5T last updated on 24/Oct/24
Question Number 212783 by Spillover last updated on 23/Oct/24 Commented by York12 last updated on 25/Oct/24
Question Number 212733 by cherokeesay last updated on 22/Oct/24 Answered by A5T last updated on 22/Oct/24 Commented by A5T last updated on 22/Oct/24 $$\left({R}−\sqrt{\mathrm{2}}\right)^{\mathrm{2}} =\mathrm{2}\left(\sqrt{\mathrm{2}}\right)^{\mathrm{2}}…
Question Number 212721 by Spillover last updated on 22/Oct/24 Answered by A5T last updated on 22/Oct/24 Commented by A5T last updated on 22/Oct/24 $${In}\left[{ABC}\right];\:{tan}\theta=\frac{{R}}{{R}+\mathrm{2}{r}};{AC}=\sqrt{\mathrm{2}{R}^{\mathrm{2}} +\mathrm{4}{r}^{\mathrm{2}}…