Question Number 167008 by mnjuly1970 last updated on 04/Mar/22 Answered by mr W last updated on 06/Mar/22 Commented by Tawa11 last updated on 06/Mar/22 $$\mathrm{Great}\:\mathrm{sir}…
Question Number 167011 by mnjuly1970 last updated on 04/Mar/22 Answered by TheSupreme last updated on 04/Mar/22 $${Talete}\:{theorem}\:{respect}\:{point}\:{A}\:{far}\:{away}\:{x}\:{from}\:{center}\: \\ $$$${of}\:{circle}\:{of}\:{radius}\:\mathrm{4} \\ $$$${let}'{s}\:{y}={PQ} \\ $$$${x}:\mathrm{4}=\left({x}+\mathrm{4}\right):{y}=\left({x}+\mathrm{12}\right):\mathrm{8} \\ $$$$\frac{{x}}{\mathrm{4}}=\frac{{x}+\mathrm{12}}{\mathrm{8}}\rightarrow{x}=\mathrm{12}…
Question Number 35871 by MJS last updated on 25/May/18 $$\mathrm{new}\:\mathrm{idea}\:\left(\mathrm{and}\:\mathrm{solution}\right)\:\mathrm{to}\:\mathrm{questions}\:\mathrm{35178}\:\&\:\:\mathrm{35195} \\ $$$$ \\ $$$$\mathrm{triangle}: \\ $$$${ABC};\:{a}={BC},\:{b}={CA},\:{c}={AB}; \\ $$$$\alpha=\angle{CAB},\:\beta=\angle{ABC},\:\gamma=\angle{BCA} \\ $$$${d}=\sqrt{\left({a}+{b}+{c}\right)\left({a}+{b}−{c}\right)\left({a}−{b}+{c}\right)\left(−{a}+{b}+{c}\right)} \\ $$$$ \\ $$$$\mathrm{put}\:\mathrm{it}\:\mathrm{as}\:\mathrm{this}: \\…
Question Number 166928 by amin96 last updated on 02/Mar/22 Answered by mr W last updated on 02/Mar/22 $${a}\:{picture}\:{says}\:{more}\:{than}\:{a}\:{thousant} \\ $$$${words}… \\ $$ Commented by mr…
Question Number 166917 by ajfour last updated on 02/Mar/22 Commented by mr W last updated on 02/Mar/22 Commented by ajfour last updated on 02/Mar/22 $$\left\{\left(\mathrm{2}{b}−{c}\right)\mathrm{cos}\:\theta−{b}\right\}^{\mathrm{2}}…
Question Number 101375 by ajfour last updated on 02/Jul/20 Commented by ajfour last updated on 02/Jul/20 $${In}\:{terms}\:{of}\:{R},\:{find}\:{radii}\:{a},{b},{c}. \\ $$ Commented by ajfour last updated on…
Question Number 166888 by cherokeesay last updated on 01/Mar/22 Answered by mr W last updated on 01/Mar/22 Commented by mr W last updated on 01/Mar/22…
Question Number 35798 by ajfour last updated on 23/May/18 Commented by ajfour last updated on 23/May/18 $$\bigtriangleup{ABC}\:{and}\:\bigtriangleup{CDE}\:{are}\:{congruent}. \\ $$$${Find}\:{the}\:{area}\:{of}\:{quadrilateral} \\ $$$${APQC}\:{in}\:{terms}\:{of}\:{a},\:{b},\:{and}\:{c}\:;\:{the} \\ $$$${sides}\:{of}\:\bigtriangleup{ABC}\:. \\ $$…
Question Number 166875 by amin96 last updated on 01/Mar/22 Commented by amin96 last updated on 01/Mar/22 $$\boldsymbol{\mathrm{circle}}\:\boldsymbol{\mathrm{radius}}=??? \\ $$ Answered by MJS_new last updated on…
Question Number 166861 by Tawa11 last updated on 01/Mar/22 Commented by cortano1 last updated on 01/Mar/22 $$\Rightarrow\mathrm{3}.\mathrm{x}=\mathrm{6}.\mathrm{2}\Rightarrow\mathrm{x}=\mathrm{4} \\ $$$$\Rightarrow\mathrm{r}=\sqrt{\mathrm{2}^{\mathrm{2}} +\mathrm{6}^{\mathrm{2}} +\mathrm{3}^{\mathrm{2}} +\mathrm{4}^{\mathrm{2}} }\:=\sqrt{\mathrm{49}+\mathrm{16}}=\sqrt{\mathrm{65}} \\ $$…