Menu Close

Category: Geometry

Question-168801

Question Number 168801 by Ari last updated on 17/Apr/22 Commented by cortano1 last updated on 18/Apr/22 $$\overset{\rightarrow} {{AO}}\:=\:\frac{\mathrm{2}}{\mathrm{3}}\overset{\rightarrow} {{AC}}\:=\:\frac{\mathrm{4}}{\mathrm{3}}\left(\overset{\rightarrow} {{a}}+\overset{\rightarrow} {{b}}\right) \\ $$ Commented by…

Question-168737

Question Number 168737 by infinityaction last updated on 16/Apr/22 Commented by infinityaction last updated on 16/Apr/22 $$\boldsymbol{\mathrm{find}}\:\boldsymbol{\mathrm{the}}\:\boldsymbol{\mathrm{value}}\:\boldsymbol{\mathrm{of}}\:\boldsymbol{\mathrm{x}} \\ $$ Answered by mr W last updated…

Question-103179

Question Number 103179 by ajfour last updated on 13/Jul/20 Commented by ajfour last updated on 13/Jul/20 $${If}\:{D}\:{and}\:{E}\:{are}\:{midpoints}\:{of}\: \\ $$$${sides}\:{AC}\:{and}\:{AB}\:\:{respectively}, \\ $$$${of}\:\bigtriangleup{ABC}\:,\:{find}\: \\ $$$$\:\:\:\:\:\:\frac{{blue}\:{area}}{{area}\:\bigtriangleup{ABC}}\:\:\:\:{in}\:{terms}\:{of}\: \\ $$$$\:{sides}\:{a},\:{b},\:{c}\:{of}\:{the}\:\bigtriangleup.…

Question-103165

Question Number 103165 by ajfour last updated on 13/Jul/20 Commented by ajfour last updated on 13/Jul/20 $${If}\:{outer}\:{circle}\:{has}\:{unit}\:{radius}, \\ $$$${find}\:{side}\:{of}\:{the}\:{equilateral}\:\bigtriangleup. \\ $$$${P},\:{Q},{R}\:{are}\:{centres}\:{of}\:{the}\: \\ $$$${smaller}\:{circles}.\:{Also}\:{find}\:\alpha. \\ $$…

Question-37553

Question Number 37553 by ajfour last updated on 14/Jun/18 Commented by ajfour last updated on 15/Jun/18 $${Find}\:{maximum}\:{area}\:{of}\:\bigtriangleup{MNP}\:{in}\: \\ $$$${terms}\:{of}\:{sides}\:{a},{b},{c}\:\left({of}\:\bigtriangleup{ABC}\right)\: \\ $$$${and}\:{radius}\:{R}\:\left({of}\:{outer}\:{circle}\right). \\ $$ Commented by…

Question-37447

Question Number 37447 by ajfour last updated on 13/Jun/18 Commented by ajfour last updated on 13/Jun/18 $${Find}\:{the}\:{maximum}\:{elliptic}\:{area} \\ $$$$\left({in}\:{the}\:{shown}\:{orientation}\right)\: \\ $$$${cicumscribed}\:{by}\:{the}\:{isosceles} \\ $$$${triangle}. \\ $$…