Category: Geometry

Question Number 105985 by Algoritm last updated on 02/Aug/20 Answered by mr W last updated on 02/Aug/20 $$r+\frac{2}{\sqrt{3}}r=\frac{6}{\sqrt{3}}$$$$r=\frac{6}{2+\sqrt{3}}=6(2-\sqrt{3})$$$$S=\pi r^2=36(7-4\sqrt{3})\pi$$…

Question Number 105945 by Algoritm last updated on 01/Aug/20 Answered by 1549442205PVT last updated on 02/Aug/20 Commented by 1549442205PVT last updated on 02/Aug/20 $$\mathrm{2R}+\mathrm{BC}=\mathrm{AB}+\mathrm{AC}\Rightarrow\mathrm{R}=\frac{\mathrm{6}+\mathrm{8}−\mathrm{10}}{\mathrm{2}}=\mathrm{2} \…

Question Number 105769 by ajfour last updated on 31/Jul/20 Commented by ajfour last updated on 31/Jul/20 $$ACDBisastraightline.The$$$$threecolouredregionshaveequal$$$$areas.GivenOA=p,OB=q.$$$$FindcoordinatesofAandB.$$…

Question Number 171255 by mnjuly1970 last updated on 11/Jun/22 Commented by mr W last updated on 11/Jun/22 $$S_{\mathrm{\Delta }APB}=\frac{AB\times AP\cos \theta }{2}$$$$=\frac{AD\times AP\cos \theta }{4}$$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:=\frac{{AP}^{\mathrm{2}} }{\mathrm{4}} \…

Question Number 105630 by I want to learn more last updated on 30/Jul/20 Commented by I want to learn more last updated on 30/Jul/20 $$\mathrm{Thanks}\:\mathrm{sir}…