Category: Geometry

Question Number 172558 by bagjagugum123 last updated on 28/Jun/22 Answered by mr W last updated on 28/Jun/22 Commented by mr W last updated on 28/Jun/22…

Question Number 106990 by I want to learn more last updated on 08/Aug/20 $$\mathrm{Two}\mathrm{places}\mathrm{A}\mathrm{and}\mathrm{B}\mathrm{both}\mathrm{on}\mathrm{a}\mathrm{parallel}\mathrm{of}\mathrm{latitude}\alpha °\mathrm{N}$$$$\mathrm{differs}\mathrm{in}\mathrm{longitudes}\mathrm{by}\theta °.\mathrm{Show}\mathrm{that}\mathrm{the}\mathrm{shortest}\mathrm{distance}$$$$\mathrm{between}\mathrm{them}\mathrm{is}:\frac{\left[2{\sin }^{-1}\left(\cos \alpha \sin \frac{\theta }{2}\right)\right]}{360}\times 2\pi \mathrm{R}$$$$$$$$\mathrm{Topic}:\mathrm{Longitude}\mathrm{and}\mathrm{Latitude}$$…

Question Number 172504 by mnjuly1970 last updated on 28/Jun/22 Answered by mr W last updated on 28/Jun/22 Commented by mr W last updated on 28/Jun/22…

Question Number 172483 by mnjuly1970 last updated on 27/Jun/22 Answered by mr W last updated on 28/Jun/22 Commented by mr W last updated on 28/Jun/22…

Question Number 172437 by infinityaction last updated on 26/Jun/22 Answered by mr W last updated on 27/Jun/22 $$R=radiusofsemicircle$$$$r=radiusofcircle$$$$O=centerofsemicircle$$$${AC}=\mathrm{2}{R}\:\mathrm{cos}\:\theta \…