Geometry – Page 168

Question-41214

Tinku Tara June 4, 2023 Geometry 0 Comments

Question Number 41214 by ajfour last updated on 03/Aug/18 Commented by ajfour last updated on 03/Aug/18 $L a r g e r s p h e r e i s i n s c r i b e d i n t h e$ $c u b e; w h i l e t h e s m a l l e r s p h e r e$ $i s t a n g e n t t o t h r e e f a c e s o f c u b e$ $a n d t o t h e l a r g e r s p h e r e . F i n d i t s$ $${radius}.…

Question-172284

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Question Number 172284 by mnjuly1970 last updated on 25/Jun/22 Answered by mr W last updated on 25/Jun/22 $s a y A C = e, B D = f$ $\cos B = \frac{a^{2} + b^{2} - e^{2}}{2 a b}$ $$\mathrm{cos}\:{D}=\frac{{c}^{\mathrm{2}}…

Question-41203

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Question Number 41203 by ajfour last updated on 03/Aug/18 Commented by ajfour last updated on 03/Aug/18 $I f A B = c i s a d i a m e t e r o f l a r g e r$ $c i r c l e a n d P Q i s a d i a m e t e r o f$ $t h e s m a l l e r c i r c l e, f i n d x i n t e r m s$ $o f c; (g e o m e t r i c a l l y) .$ …

Question-172225

Tinku Tara June 4, 2023 Geometry 0 Comments

Question Number 172225 by mnjuly1970 last updated on 24/Jun/22 Answered by infinityaction last updated on 24/Jun/22 Commented by mnjuly1970 last updated on 24/Jun/22 $${thanks}\:{alot}\:{sir} \…

Question-41146

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Question Number 41146 by ajfour last updated on 02/Aug/18 Commented by ajfour last updated on 02/Aug/18 $Q . 41138 s o l u t i o n$ Answered by ajfour last updated on…

Question-172202

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Question Number 172202 by mr W last updated on 24/Jun/22 Commented by infinityaction last updated on 24/Jun/22 $? = \sqrt{\frac{14 \times 16}{14}} = 4$ Answered by Rasheed.Sindhi last updated…

Question-106663

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Question Number 106663 by I want to learn more last updated on 06/Aug/20 Answered by Her_Majesty last updated on 06/Aug/20 $\frac{y}{6} = \frac{6}{x} \Rightarrow y = \frac{36}{x}$ $$\left({x}+\mathrm{6}\right)^{\mathrm{2}} +\left({y}+\mathrm{6}\right)^{\mathrm{2}} =\mathrm{20}^{\mathrm{2}}…

Question-172195

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Question Number 172195 by cherokeesay last updated on 24/Jun/22 Answered by som(math1967) last updated on 24/Jun/22 $l e t s i d e o f b i g g e s t s q u a r e = r a d . o f$ $q u a r t e r c i r c l e = r u n i t$ $∴ A B = A L = r$ $$\therefore\:{side}\:{of}\:{S}_{\mathrm{2}} =\frac{{r}}{\:\sqrt{\mathrm{2}}} \…

Question-41096

Tinku Tara June 4, 2023 Geometry 0 Comments

Question Number 41096 by ajfour last updated on 02/Aug/18 Commented by ajfour last updated on 02/Aug/18 $A B = c a n d C E = F D = 1$ $F i n d G C = D H i n t e r m s o f c;$ $(g e o m e t r i c a l l y) .$ Terms of…

Question-172144

Tinku Tara June 4, 2023 Geometry 0 Comments

Question Number 172144 by mnjuly1970 last updated on 23/Jun/22 Answered by infinityaction last updated on 23/Jun/22 Commented by infinityaction last updated on 23/Jun/22 $$\:\:\:\mathrm{cos}\alpha\:=\:\frac{\mathrm{2}}{{r}}\:\:\:{and}\:\:\:\:\mathrm{sin}\alpha\:\:=\:\:\frac{{r}}{\mathrm{6}}\: \…

Category: Geometry