Question Number 208467 by Tawa11 last updated on 16/Jun/24 Answered by A5T last updated on 17/Jun/24 Commented by A5T last updated on 17/Jun/24 $${sin}\theta=\frac{\mathrm{3}\sqrt{\mathrm{10}}}{\:\mathrm{10}}\Rightarrow{cos}\theta=\frac{\sqrt{\mathrm{10}}}{\mathrm{10}} \\…
Question Number 208455 by efronzo1 last updated on 16/Jun/24 Commented by mr W last updated on 16/Jun/24 $${the}\:{green}\:{one}\:{even}\:{doesn}'{t}\:{need}\:{to}\:{be}\: \\ $$$${a}\:{semicircle}. \\ $$ Commented by mr…
Question Number 208385 by efronzo1 last updated on 14/Jun/24 Commented by efronzo1 last updated on 15/Jun/24 Commented by efronzo1 last updated on 15/Jun/24 $$\mathrm{i}'\mathrm{m}\:\mathrm{stuck}\:\mathrm{this}\:\mathrm{step} \\…
Question Number 208344 by mr W last updated on 13/Jun/24 Commented by mr W last updated on 13/Jun/24 $${find}\:{green}\:{area}=? \\ $$ Commented by naka3546 last…
Question Number 208288 by efronzo1 last updated on 10/Jun/24 Answered by A5T last updated on 10/Jun/24 $$\mathrm{8}\left(\mathrm{8}+{x}\right)=\left(\mathrm{2}{r}\right)\left(\mathrm{2}{r}+\mathrm{2}{R}\right)=\mathrm{4}{r}^{\mathrm{2}} +\mathrm{4}{rR} \\ $$$$\Rightarrow{x}=\frac{{r}^{\mathrm{2}} +{rR}−\mathrm{16}}{\mathrm{2}}…\left({i}\right) \\ $$$$\left(\mathrm{8}+{x}\right)^{\mathrm{2}} ={R}^{\mathrm{2}} +\left(\mathrm{2}{r}+{R}\right)^{\mathrm{2}}…
Question Number 208158 by necx122 last updated on 06/Jun/24 $${X},\:{Y}\:{and}\:{Z}\:{are}\:{points}\:{on}\:{the}\:{sides}\:{AB}, \\ $$$${BC}\:{and}\:{AC}\:{of}\:{the}\:{triangle}\:{ABC},\:{such} \\ $$$${that}\:{AX}:{XB}\:=\mathrm{4}:\mathrm{3},\:{BY}:{YC}=\mathrm{2}:\mathrm{3},\: \\ $$$${CZ}:{ZA}=\mathrm{2}:\mathrm{1}.\:{Find}\:{the}\:{ratio}\:{of}\:{the}\:{area} \\ $$$${of}\:{the}\:{triangle}\:{XYZ}\:{to}\:{that}\:{of}\:{triangle} \\ $$$${ABC}. \\ $$ Answered by mr…
Question Number 208111 by mr W last updated on 05/Jun/24 Commented by mr W last updated on 05/Jun/24 $${yellow}\:{area}\:=? \\ $$ Answered by A5T last…
Question Number 208100 by efronzo1 last updated on 05/Jun/24 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 208049 by mr W last updated on 03/Jun/24 Commented by Frix last updated on 03/Jun/24 $${a}=\mathrm{1}\wedge{b}=\mathrm{3} \\ $$$${r}={a}+{b}−\sqrt{{a}^{\mathrm{2}} +{b}^{\mathrm{2}} }=\mathrm{4}−\sqrt{\mathrm{10}} \\ $$ Answered…
Question Number 208023 by efronzo1 last updated on 02/Jun/24 Answered by mr W last updated on 02/Jun/24 $${x}={a}+\mid{r}\mid\:\mathrm{cos}\:\theta \\ $$$$\Rightarrow{y}={b}+\mid{r}\mid\:\mathrm{sin}\:\theta \\ $$$$\sqrt{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} } \\…