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Category: Geometry

Question-34585

Question Number 34585 by tawa tawa last updated on 08/May/18 Commented by Rasheed.Sindhi last updated on 08/May/18 $$\mathcal{N}{ot}\:{related}\:{to}\:{above}…. \\ $$$$\mathrm{Q}#\mathrm{34429}\:\mathrm{by}\:\mathrm{S}@\mathrm{ty}@\mathrm{m}:\:\mathrm{3}^{\mathrm{m}} +\mathrm{3}^{\mathrm{n}} +\mathrm{1}\:\mathrm{is}\:\mathrm{not} \\ $$$$\mathrm{a}\:\mathrm{perfect}\:\mathrm{square}.\:\mathrm{I}'\mathrm{ve}\:\mathrm{tried}\:\mathrm{to}\:\mathrm{provide} \\…

Question-165514

Question Number 165514 by Tawa11 last updated on 02/Feb/22 Answered by som(math1967) last updated on 03/Feb/22 $$\left.\boldsymbol{{a}}\right)\:\:\boldsymbol{{let}}\:\boldsymbol{{radius}}\:\boldsymbol{{OC}}=\boldsymbol{{x}} \\ $$$$\therefore\boldsymbol{{OD}}=\left(\boldsymbol{{x}}−\mathrm{2}\right) \\ $$$$\boldsymbol{{from}}\bigtriangleup\boldsymbol{{OED}} \\ $$$$\:\:\boldsymbol{{x}}^{\mathrm{2}} =\mathrm{6}^{\mathrm{2}} +\left(\boldsymbol{{x}}−\mathrm{2}\right)^{\mathrm{2}}…