Question Number 207008 by mr W last updated on 03/May/24 Answered by A5T last updated on 03/May/24 Commented by A5T last updated on 03/May/24 $$\frac{\mathrm{5}}{{BO}}=\frac{\mathrm{6}}{{CO}}\Rightarrow\frac{{BO}}{{CO}}=\frac{\mathrm{5}}{\mathrm{6}};\:{BO}=\mathrm{5}{x};{CO}=\mathrm{6}{x}…
Question Number 206956 by mr W last updated on 01/May/24 Commented by mr W last updated on 01/May/24 $${find}\:{the}\:{radius}\:{of}\:{circle}. \\ $$ Answered by Frix last…
Question Number 206937 by efronzo1 last updated on 01/May/24 Answered by A5T last updated on 01/May/24 Commented by A5T last updated on 01/May/24 $$\mathrm{8}×\mathrm{14}={x}\left({x}+\mathrm{2}{r}\right)={x}^{\mathrm{2}} +\mathrm{2}{rx}=\mathrm{112}…
Question Number 206923 by Amidip last updated on 01/May/24 $$ \\ $$$$ \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 206885 by efronzo1 last updated on 29/Apr/24 Answered by BaliramKumar last updated on 29/Apr/24 $${x}\:=\:\mathrm{tan}^{−\mathrm{1}} \left(\frac{\mathrm{5}}{\mathrm{8}}\right)\:\approx\:\mathrm{32}° \\ $$ Answered by Rasheed.Sindhi last updated…
Question Number 206806 by Frix last updated on 26/Apr/24 $$\mathrm{Given}\:\mathrm{is}\:\mathrm{a}\:\mathrm{square}\:\mathrm{with}\:\mathrm{side}\:\mathrm{length}\:\mathrm{15}. \\ $$$$\mathrm{We}\:\mathrm{need}\:\mathrm{to}\:\mathrm{find}\:\mathrm{exactly}\:\mathrm{17}\:\mathrm{smaller}\:\mathrm{squares} \\ $$$$\mathrm{to}\:\mathrm{fill}\:\mathrm{the}\:\mathrm{big}\:\mathrm{one}.\:\mathrm{How}\:\mathrm{many}\:\mathrm{solutions}\:\mathrm{are} \\ $$$$\mathrm{possible}? \\ $$$$\left(\mathrm{Note}:\:\mathrm{it}'\mathrm{s}\:\mathrm{not}\:\mathrm{enough}\:\mathrm{to}\:\mathrm{find}\:\mathrm{squares}\:\mathrm{with}\right. \\ $$$$\mathrm{the}\:\mathrm{sum}\:\mathrm{of}\:\mathrm{their}\:\mathrm{areas}\:\mathrm{being}\:\mathrm{225},\:\mathrm{they}\:\mathrm{must} \\ $$$$\mathrm{fit}\:\mathrm{into}\:\mathrm{the}\:\mathrm{15}×\mathrm{15}\:\mathrm{square}.\:\mathrm{Example}\:\mathrm{with} \\ $$$$\mathrm{3}\:\mathrm{squares}:\:\mathrm{2}×\mathrm{2}+\mathrm{5}×\mathrm{5}+\mathrm{14}×\mathrm{14}=\mathrm{225}\:\mathrm{but} \\…
Question Number 206804 by mr W last updated on 25/Apr/24 Answered by mr W last updated on 26/Apr/24 Commented by mr W last updated on…
Question Number 206750 by mr W last updated on 23/Apr/24 Answered by HeferH24 last updated on 23/Apr/24 $$\:{By}\:{similar}\:{triangles}: \\ $$$$\:\frac{{d}}{{c}}\:=\:\frac{{x}}{{b}}\:;\:\:\frac{{d}}{{c}}\:=\:\frac{{a}}{{x}}\: \\ $$$$\:\frac{{a}}{{x}}\:=\:\frac{{x}}{{b}}\:\Leftrightarrow\:{x}^{\mathrm{2}} \:=\:{ab}\:\Leftrightarrow\:{x}=\sqrt{{ab}} \\ $$…
Question Number 206737 by mr W last updated on 23/Apr/24 Commented by A5T last updated on 23/Apr/24 $${Is}\:{that}\:{signified}\:{angle}\:\mathrm{90}°\:{or}\:{any}? \\ $$ Commented by mr W last…
Question Number 206729 by mr W last updated on 23/Apr/24 Answered by A5T last updated on 23/Apr/24 $$\frac{{sin}\mathrm{84}}{{AD}}=\frac{{sin}\mathrm{54}}{{AC}}\Rightarrow{AD}=\frac{{ACsin}\mathrm{84}}{{sin}\mathrm{54}}…\left({i}\right) \\ $$$$\frac{{sin}\left(?\right)}{{AD}}=\frac{{sin}\left(\mathrm{54}−?\right)}{{BD}={AC}}\Rightarrow{AD}=\frac{{ACsin}\left(?\right)}{{sin}\left(\mathrm{54}−?\right)}…\left({ii}\right) \\ $$$$\left({i}\right)\&\left({ii}\right)\Rightarrow\frac{{sin}\mathrm{84}}{{sin}\mathrm{54}}=\frac{{sin}\left(?\right)}{{sin}\left(\mathrm{54}−?\right)}\Rightarrow?=\mathrm{30}° \\ $$ Commented…