Category: Geometry

Question Number 97557 by Power last updated on 08/Jun/20 Answered by mr W last updated on 08/Jun/20 $$\angle{CBE}=\angle{EBD}=\theta=\frac{\mathrm{1}}{\mathrm{2}}\left(\frac{\pi}{\mathrm{2}}−\alpha\right) \\ $$$$\Rightarrow\mathrm{2}\theta=\frac{\pi}{\mathrm{2}}−\alpha \\ $$$${BD}=\mathrm{2}{r}\:\mathrm{sin}\:\alpha \\ $$$${EB}=\frac{\mathrm{2}{r}}{\mathrm{cos}\:\theta} \\…

Question Number 97192 by bagjamath last updated on 07/Jun/20 Commented by bagjamath last updated on 07/Jun/20 $${a}+{b}+{c}+{d}+{e}=… \\ $$ Commented by prakash jain last updated…

Question Number 162530 by mr W last updated on 30/Dec/21 Commented by mr W last updated on 30/Dec/21 $${find}\:{the}\:{sum}\:{of}\:{areas}\:{of}\:{all}\:\left({infinite}\right) \\ $$$${red}\:{circles} \\ $$ Commented by…

Question Number 162481 by mnjuly1970 last updated on 29/Dec/21 Answered by mr W last updated on 29/Dec/21 $${length}\:{of}\:{base}\:={h} \\ $$$$\mathrm{tan}\:\alpha=\frac{{b}}{{h}} \\ $$$$\mathrm{tan}\:\mathrm{2}\alpha=\frac{{b}+{a}}{{h}} \\ $$$$\mathrm{tan}\:\mathrm{3}\alpha=\frac{{b}+{a}+{x}}{{h}} \\…

Question Number 96920 by Power last updated on 05/Jun/20 Commented by mr W last updated on 05/Jun/20 $${too}\:{less}\:{info}\:\Rightarrow{no}\:{unique}\:{solution}! \\ $$ Commented by mr W last…