Question Number 172225 by mnjuly1970 last updated on 24/Jun/22 Answered by infinityaction last updated on 24/Jun/22 Commented by mnjuly1970 last updated on 24/Jun/22 $${thanks}\:{alot}\:{sir} \\…
Question Number 41146 by ajfour last updated on 02/Aug/18 Commented by ajfour last updated on 02/Aug/18 $${Q}.\mathrm{41138}\:\:\:{solution} \\ $$ Answered by ajfour last updated on…
Question Number 172202 by mr W last updated on 24/Jun/22 Commented by infinityaction last updated on 24/Jun/22 $$?=\:\sqrt{\frac{\mathrm{14}×\mathrm{16}}{\mathrm{14}}\:}\:\:=\:\:\mathrm{4}\: \\ $$ Answered by Rasheed.Sindhi last updated…
Question Number 106663 by I want to learn more last updated on 06/Aug/20 Answered by Her_Majesty last updated on 06/Aug/20 $$\frac{{y}}{\mathrm{6}}=\frac{\mathrm{6}}{{x}}\:\Rightarrow\:{y}=\frac{\mathrm{36}}{{x}} \\ $$$$\left({x}+\mathrm{6}\right)^{\mathrm{2}} +\left({y}+\mathrm{6}\right)^{\mathrm{2}} =\mathrm{20}^{\mathrm{2}}…
Question Number 172195 by cherokeesay last updated on 24/Jun/22 Answered by som(math1967) last updated on 24/Jun/22 $${let}\:{side}\:{of}\:{biggest}\:{square}={rad}.\:{of} \\ $$$${quarter}\:{circle}\:={r}\:{unit} \\ $$$$\therefore\:{AB}={AL}={r} \\ $$$$\therefore\:{side}\:{of}\:{S}_{\mathrm{2}} =\frac{{r}}{\:\sqrt{\mathrm{2}}} \\…
Question Number 41096 by ajfour last updated on 02/Aug/18 Commented by ajfour last updated on 02/Aug/18 $${AB}={c}\:\:{and}\:\:{CE}={FD}=\mathrm{1} \\ $$$${Find}\:{GC}={DH}\:{in}\:{terms}\:{of}\:{c}\:; \\ $$$$\left({geometrically}\right). \\ $$ Terms of…
Question Number 172144 by mnjuly1970 last updated on 23/Jun/22 Answered by infinityaction last updated on 23/Jun/22 Commented by infinityaction last updated on 23/Jun/22 $$\:\:\:\mathrm{cos}\alpha\:=\:\frac{\mathrm{2}}{{r}}\:\:\:{and}\:\:\:\:\mathrm{sin}\alpha\:\:=\:\:\frac{{r}}{\mathrm{6}}\: \\…
Question Number 41062 by Tawa1 last updated on 01/Aug/18 Commented by tanmay.chaudhury50@gmail.com last updated on 01/Aug/18 Commented by tanmay.chaudhury50@gmail.com last updated on 01/Aug/18 $${pls}\:{wait}\:{destination}\:{yet}\:{to}\:{reach}… \\…
Question Number 41063 by Tawa1 last updated on 01/Aug/18 Commented by alex041103 last updated on 07/Aug/18 $$\mathrm{72} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 41038 by Tawa1 last updated on 31/Jul/18 Commented by tanmay.chaudhury50@gmail.com last updated on 31/Jul/18 $$\left.{about}\:{question}\:{number}\:\mathrm{25}\right) \\ $$$${there}\:{is}\:{eight}\:{corner}…{at}\:{each}\:{corner}\:{three}\:{face} \\ $$$${merge}…{number}\:{at}\:{any}\:{corner}\:{share}\:{by}\:{three} \\ $$$${face}..{target}\:{to}\:{find}\:{sum}\:{of}\:{four}\:{number}\:{such} \\ $$$${that}\:{each}\:{face}\:{give}\:{same}\:{value}…{the}\:{sumtotal}…