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Category: Geometry

Question-155701

Question Number 155701 by ajfour last updated on 03/Oct/21 Commented by ajfour last updated on 03/Oct/21 $${If}\:{the}\:{blue}\:{triangle}\:{is}\:{equilateral} \\ $$$${find}\:{the}\:{radius}\:{ratio}. \\ $$$$\left({the}\:{center}\:{of}\:{both}\:{circles}\:{lie}\:{on}\:{the}\right. \\ $$$$\left.\:\:\:{same}\:{vertical}\right) \\ $$…

Question-90161

Question Number 90161 by I want to learn more last updated on 21/Apr/20 Answered by me2love2math last updated on 21/Apr/20 $${the}\:{square}\:{has}\:{a}\:{larger}\:{perimeter}…. \\ $$$${draw}\:\boldsymbol{{a}}\:\boldsymbol{{chord}}\:\boldsymbol{{that}}\:\boldsymbol{{run}}\:\boldsymbol{{through}}\:\boldsymbol{{the}}\:\boldsymbol{{centre}}\:\boldsymbol{{o}} \\ $$$$\boldsymbol{{centre}}\:\boldsymbol{{of}}\:\boldsymbol{{circle}}\:\boldsymbol{{and}}\:\boldsymbol{{apply}}\:\boldsymbol{{law}}\:\boldsymbol{{of}}\:…

Question-155628

Question Number 155628 by amin96 last updated on 03/Oct/21 Answered by mr W last updated on 03/Oct/21 $${BM}={MC}=\mathrm{1} \\ $$$${AC}=\mathrm{2}\sqrt{\mathrm{2}} \\ $$$$\frac{\mathrm{1}}{\mathrm{cos}\:\left(\mathrm{45}+{x}\right)\:\mathrm{sin}\:\mathrm{30}}=\frac{\mathrm{2}\sqrt{\mathrm{2}}}{\mathrm{sin}\:\left(\mathrm{30}+{x}\right)} \\ $$$$\frac{\mathrm{1}}{\mathrm{cos}\:{x}−\mathrm{sin}\:{x}}=\frac{\mathrm{2}}{\mathrm{cos}\:{x}+\sqrt{\mathrm{3}}\:\mathrm{sin}\:{x}} \\…