Question Number 30808 by 33 last updated on 26/Feb/18 Answered by mrW2 last updated on 26/Feb/18 Commented by mrW2 last updated on 26/Feb/18 $${x}_{\mathrm{1}} =\mathrm{2}{a}\:\mathrm{cos}\:\theta…
Question Number 30719 by mrW2 last updated on 24/Feb/18 Commented by mrW2 last updated on 25/Feb/18
Question Number 161742 by mr W last updated on 21/Dec/21 Commented by mr W last updated on 21/Dec/21
Question Number 161482 by amin96 last updated on 18/Dec/21 Commented by amin96 last updated on 18/Dec/21
Question Number 161424 by cherokeesay last updated on 17/Dec/21 Answered by aleks041103 last updated on 17/Dec/21
Question Number 161367 by amin96 last updated on 17/Dec/21 Commented by 1549442205PVT last updated on 17/Dec/21
Question Number 95830 by I want to learn more last updated on 27/May/20 Answered by behi83417@gmail.com last updated on 28/May/20 $$\mathrm{4s}+\frac{\mathrm{16}^{\mathrm{2}} }{\mathrm{2}}=\mathrm{16}^{\mathrm{2}} \Rightarrow\mathrm{s}=\frac{\mathrm{16}^{\mathrm{2}} }{\mathrm{8}}=\mathrm{32} \…
Question Number 95772 by I want to learn more last updated on 27/May/20 Commented by I want to learn more last updated on 27/May/20 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{shaded}…
Question Number 161296 by amin96 last updated on 15/Dec/21 Answered by mr W last updated on 16/Dec/21
Question Number 161257 by amin96 last updated on 15/Dec/21 Commented by amin96 last updated on 15/Dec/21