Question Number 23677 by Anoop kumar last updated on 03/Nov/17 $${solve} \\ $$$$\:\:\:\:\:\:\:\:\:\: \\ $$$$\underset{{x}\rightarrow{inf}+} {\mathrm{li}{m}}\:\:\underset{\mathrm{2}{sin}\frac{\mathrm{1}}{{x}}} {\int}^{\mathrm{2}\sqrt{{x}}} \frac{\mathrm{2}{t}^{\mathrm{4}} +\mathrm{1}}{\left({t}−\mathrm{3}\right)\left({t}^{\mathrm{3}} +\mathrm{3}\right)}\:{dt} \\ $$ Terms of Service…
Question Number 23663 by Anoop kumar last updated on 03/Nov/17 $${solve} \\ $$$$ \\ $$$$\underset{−\mathrm{1}} {\int}^{\mathrm{1}_{} } {x}^{\mathrm{2}} {d}\left({lnx}\right) \\ $$$$ \\ $$$$ \\ $$$$…
Question Number 23592 by Tinkutara last updated on 02/Nov/17 $$\mathrm{Let}\:{ABC}\:\mathrm{be}\:\mathrm{a}\:\mathrm{triangle}\:\mathrm{with}\:{AB}\:=\:{AC} \\ $$$$\mathrm{and}\:\angle{BAC}\:=\:\mathrm{30}°.\:\mathrm{Let}\:{A}'\:\mathrm{be}\:\mathrm{the}\:\mathrm{reflection} \\ $$$$\mathrm{of}\:{A}\:\mathrm{in}\:\mathrm{the}\:\mathrm{line}\:{BC};\:{B}'\:\mathrm{be}\:\mathrm{the}\:\mathrm{reflection} \\ $$$$\mathrm{of}\:{B}\:\mathrm{in}\:\mathrm{the}\:\mathrm{line}\:{CA};\:{C}'\:\mathrm{be}\:\mathrm{the}\:\mathrm{reflection} \\ $$$$\mathrm{of}\:{C}\:\mathrm{in}\:\mathrm{the}\:\mathrm{line}\:{AB}.\:\mathrm{Show}\:\mathrm{that}\:{A}',\:{B}',\:{C}' \\ $$$$\mathrm{form}\:\mathrm{the}\:\mathrm{vertices}\:\mathrm{of}\:\mathrm{an}\:\mathrm{equilateral} \\ $$$$\mathrm{triangle}. \\ $$ Answered…
Question Number 89097 by TawaTawa1 last updated on 15/Apr/20 Commented by mr W last updated on 15/Apr/20 $$\sqrt{\mathrm{5}^{\mathrm{2}} +\left(\mathrm{10}+\mathrm{5}\right)^{\mathrm{2}} }=\mathrm{5}\sqrt{\mathrm{10}} \\ $$$${s}=\mathrm{5}\sqrt{\mathrm{10}}−\frac{\mathrm{5}}{\mathrm{5}\sqrt{\mathrm{10}}}\left(\mathrm{15}+\mathrm{5}\right)=\mathrm{3}\sqrt{\mathrm{10}} \\ $$$${area}\:={s}^{\mathrm{2}} =\mathrm{9}×\mathrm{10}=\mathrm{90}…
Question Number 23539 by tapan das last updated on 01/Nov/17 $$\int\mathrm{tan}\:^{\mathrm{6}} \mathrm{x}\:\mathrm{dx} \\ $$ Answered by $@ty@m last updated on 01/Nov/17 $$\int\mathrm{tan}\:^{\mathrm{4}} {x}\left(\mathrm{sec}\:^{\mathrm{2}} {x}−\mathrm{1}\right){dx} \\…
Question Number 154594 by Lekhraj last updated on 19/Sep/21 Commented by mathdanisur last updated on 24/Sep/21 $$=\:\mathrm{1} \\ $$ Commented by peter frank last updated…
Question Number 23477 by kami last updated on 31/Oct/17 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:{x}, \\ $$$$\:\:\:\:\:\:\:\int_{−\infty} ^{{x}} {d}\mathrm{x}\:=\:\int\mid\pm\:\mathrm{sinh}\:\mathrm{cot}\:\mathrm{ln}\:\left(\mathrm{15}−\sqrt{\mathrm{33}+{x}}\right)\mid\:\mathrm{dx} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 23418 by tapan das last updated on 30/Oct/17 $$\int\mathrm{sec}\:^{\mathrm{2}} \sqrt{\mathrm{x}}\:/\sqrt{\mathrm{x}}\:\mathrm{dx} \\ $$ Answered by $@ty@m last updated on 30/Oct/17 $${Assume}\:\sqrt{{x}}={t}\:\&\:{proceed}. \\ $$$${Ans}\:\mathrm{2tan}\:\sqrt{{x}}+{C} \\…
Question Number 23408 by selestian last updated on 29/Oct/17 Answered by mrW1 last updated on 31/Oct/17 $$\mathrm{FE}=\frac{\mathrm{5}}{\mathrm{10}}×\mathrm{18}=\mathrm{9} \\ $$$$\mathrm{AC}=\frac{\mathrm{15}}{\mathrm{9}}×\left(\mathrm{5}+\mathrm{10}\right)=\mathrm{25} \\ $$$$\Rightarrow\mathrm{Answer}\:\left(\mathrm{b}\right) \\ $$ Terms of…
Question Number 154475 by mr W last updated on 18/Sep/21 Commented by mr W last updated on 18/Sep/21 $${find}\:{the}\:{area}\:{of}\:{the}\:{big}\:{triangle}\:{whose} \\ $$$${sides}\:{have}\:{the}\:{distances}\:\boldsymbol{{d}}_{\mathrm{1}} ,\boldsymbol{{d}}_{\mathrm{2}} ,\boldsymbol{{d}}_{\mathrm{3}} \:{to}\: \\…