Category: Geometry

Question Number 161296 by amin96 last updated on 15/Dec/21 Answered by mr W last updated on 16/Dec/21 $$A(p^2,p)$$$$C(q^2,q)$$$$\mathrm{tan}\:\theta=\frac{{dy}}{{dx}}=\frac{\mathrm{1}}{\mathrm{2}\sqrt{{x}}}=\frac{\mathrm{1}}{\mathrm{2}{p}}=\mathrm{1} \…

Question Number 30090 by gopikrishnan005@gmail.com last updated on 16/Feb/18 $$\mathrm{if}\mathrm{\Delta }\mathrm{ABC}\mathrm{similar}\mathrm{\Delta }\mathrm{PQR}\mathrm{and}\mathrm{area}\mathrm{of}\mathrm{\Delta }\mathrm{PQR}=4\mathrm{area}\left(\mathrm{\Delta }\mathrm{ABC}\right)\mathrm{then}\mathrm{AB}:\mathrm{PQ}\mathrm{is}$$ Answered by Rasheed.Sindhi last updated on 17/Feb/18 $$\mathrm{mAB}=\mathrm{c},\mathrm{mBC}=\mathrm{a},\mathrm{mAC}=\mathrm{b},\mathrm{s}=\frac{\mathrm{a}+\mathrm{b}+\mathrm{c}}{2}$$$$\mathrm{mPQ}=\mathrm{r},\mathrm{mQR}=\mathrm{p},\mathrm{mPR}=\mathrm{q},\mathrm{S}=\frac{\mathrm{p}+\mathrm{q}+\mathrm{r}}{2}$$$$\blacktriangle\mathrm{ABC} \…

Question Number 161033 by cherokeesay last updated on 11/Dec/21 Answered by FongXD last updated on 11/Dec/21 Commented by Tawa11 last updated on 11/Dec/21 $$\mathrm{Great}\:\mathrm{sir} \…

Question Number 160839 by amin96 last updated on 07/Dec/21 Commented by amin96 last updated on 07/Dec/21 $$\mathbf{yellow}\mathbf{area}=?$$ Answered by mr W last updated…

Question Number 95177 by mr W last updated on 23/May/20 Commented by mr W last updated on 23/May/20 $$A,B,C,Darecentersofthesquares.$$$$ProvethatAC=BDandAC\mathrm{\perp }BD.$$ Commented by…