Question Number 21754 by >>Umar >Umar
Question Number 87222 by TawaTawa1 last updated on 03/Apr/20 Commented by TawaTawa1 last updated on 03/Apr/20 $$\mathrm{Circles}\:\:\omega_{\mathrm{1}} \:\:\mathrm{and}\:\:\omega_{\mathrm{2}} \:\:\mathrm{intersect}\:\mathrm{each}\:\mathrm{other}\:\mathrm{at}\:\mathrm{points}\:\:\mathrm{A}\:\:\mathrm{and}\:\:\mathrm{B}. \\ $$$$\mathrm{Point}\:\:\mathrm{C}\:\:\mathrm{lies}\:\mathrm{on}\:\mathrm{the}\:\mathrm{tangent}\:\mathrm{line}\:\mathrm{from}\:\:\mathrm{A}\:\:\mathrm{to}\:\:\omega_{\mathrm{1}} \:\:\mathrm{such}\:\mathrm{that} \\ $$$$\angle\mathrm{ABC}\:\:=\:\:\mathrm{90}°.\:\:\mathrm{Arbitrary}\:\mathrm{line}\:\:\mathrm{L}\:\:\mathrm{passes}\:\mathrm{through}\:\:\mathrm{C}\:\:\mathrm{and} \\…
Question Number 152740 by mr W last updated on 31/Aug/21 Commented by mr W last updated on 31/Aug/21 $$\left[{Q}\mathrm{152712}\right] \\ $$ Answered by mr W…
Question Number 21656 by Joel577 last updated on 30/Sep/17 $$\mathrm{Let}\:{A}\left({x}\right)\:\mathrm{is}\:\mathrm{a}\:\mathrm{cubic}\:\mathrm{polynomial}\:\mathrm{and}\:{B}\left({x}\right)\:=\:\left({x}\:−\mathrm{1}\right)\left({x}\:−\:\mathrm{2}\right)\left({x}\:−\:\mathrm{3}\right) \\ $$$$\mathrm{Find}\:\mathrm{how}\:\mathrm{many}\:{C}\left({x}\right)\:\mathrm{so}\:\mathrm{that} \\ $$$${B}\left({C}\left({x}\right)\right)\:=\:{B}\left({x}\right)\:.\:{A}\left({x}\right) \\ $$ Commented by Joel577 last updated on 01/Oct/17 $${The}\:{answer}\:{isn}'{t}\:{given}\:{to}\:{me}.\: \\…
Question Number 21655 by Joel577 last updated on 30/Sep/17 $$\begin{pmatrix}{\mathrm{2017}}\\{\:\:\:\:\mathrm{0}}\end{pmatrix}\:+\:\begin{pmatrix}{\mathrm{2017}}\\{\:\:\:\:\mathrm{2}}\end{pmatrix}\:+\:\begin{pmatrix}{\mathrm{2017}}\\{\:\:\:\:\mathrm{4}}\end{pmatrix}\:+\:\begin{pmatrix}{\mathrm{2017}}\\{\:\:\:\:\mathrm{6}}\end{pmatrix}\:+\:…\:+\:\begin{pmatrix}{\mathrm{2017}}\\{\mathrm{2016}}\end{pmatrix} \\ $$$$\mathrm{is}\:\mathrm{equal}\:\mathrm{to}\:… \\ $$ Answered by $@ty@m last updated on 30/Sep/17 $$\left(\mathrm{1}+{x}\right)^{{n}} =\:^{{n}} {C}_{\mathrm{0}} +\:^{{n}}…
Question Number 152712 by Tawa11 last updated on 31/Aug/21 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 21611 by Nayon last updated on 29/Sep/17 $$\mathrm{Sin5}°\:=? \\ $$ Answered by $@ty@m last updated on 29/Sep/17 Terms of Service Privacy Policy Contact:…
Question Number 152647 by mr W last updated on 30/Aug/21 Commented by mr W last updated on 30/Aug/21 $${find}\:\frac{{FG}}{{GB}}=? \\ $$ Answered by mr W…
Question Number 21574 by Tinkutara last updated on 27/Sep/17 $$\mathrm{The}\:\mathrm{cyclic}\:\mathrm{octagon}\:{ABCDEFGH}\:\mathrm{has} \\ $$$$\mathrm{sides}\:{a},\:{a},\:{a},\:{a},\:{b},\:{b},\:{b},\:{b}\:\mathrm{respectively}. \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circle}\:\mathrm{that} \\ $$$$\mathrm{circumscribes}\:{ABCDEFGH}\:\mathrm{in}\:\mathrm{terms} \\ $$$$\mathrm{of}\:{a}\:\mathrm{and}\:{b}. \\ $$ Answered by mrW1 last updated…
Question Number 21571 by Tinkutara last updated on 27/Sep/17 $${ABCD}\:\mathrm{is}\:\mathrm{a}\:\mathrm{cyclic}\:\mathrm{quadrilateral};\:{x},\:{y},\:{z} \\ $$$$\mathrm{are}\:\mathrm{the}\:\mathrm{distances}\:\mathrm{of}\:{A}\:\mathrm{from}\:\mathrm{the}\:\mathrm{lines} \\ $$$${BD},\:{BC},\:{CD}\:\mathrm{respectively}.\:\mathrm{Prove}\:\mathrm{that} \\ $$$$\frac{{BD}}{{x}}\:=\:\frac{{BC}}{{y}}\:+\:\frac{{CD}}{{z}}. \\ $$ Answered by revenge last updated on 29/Sep/17…