Question Number 90330 by I want to learn more last updated on 22/Apr/20 Commented by mr W last updated on 23/Apr/20 $${if}\:{trapezium}:\: \\ $$$${x}+\mathrm{2}=\mathrm{8} \\…
Question Number 24778 by ajfour last updated on 25/Nov/17 $${Show}\:{that}\:{the}\:{shortest}\:{distance} \\ $$$${between}\:{two}\:{opposite}\:{edges}\:\boldsymbol{{a}},\boldsymbol{{d}}\: \\ $$$${of}\:{a}\:{tetrahedron}\:{is}\:\mathrm{6}\boldsymbol{{V}}/\boldsymbol{{ad}}\mathrm{sin}\:\boldsymbol{\theta}, \\ $$$${where}\:\theta\:{is}\:{the}\:{angle}\:{between}\:{the} \\ $$$${edges}\:{and}\:{V}\:{is}\:{the}\:{volume}\:{of}\:{the} \\ $$$${tetrahedron}. \\ $$ Commented by ajfour…
Question Number 90272 by student work last updated on 22/Apr/20 Answered by behi83417@gmail.com last updated on 22/Apr/20 $$\mathrm{AO}+\mathrm{OC}=\mathrm{8} \\ $$$$\mathrm{AO}^{\mathrm{2}} +\mathrm{OC}^{\mathrm{2}} =\mathrm{6}^{\mathrm{2}} \\ $$$$\Rightarrow\mathrm{AO}.\mathrm{OC}=\frac{\mathrm{1}}{\mathrm{2}}\left[\left(\mathrm{AO}+\mathrm{OC}\right)^{\mathrm{2}} −\left(\mathrm{AO}^{\mathrm{2}}…
Question Number 155770 by amin96 last updated on 04/Oct/21 Commented by amin96 last updated on 04/Oct/21 $$\boldsymbol{\mathrm{P}}{rove}\:{that}\:\:\:\mathrm{2}\boldsymbol{\mathrm{mn}}=\boldsymbol{\mathrm{D}}×\boldsymbol{\mathrm{d}} \\ $$ Answered by mr W last updated…
Question Number 24684 by Tinkutara last updated on 24/Nov/17 $$\mathrm{Let}\:{ABCD}\:\mathrm{be}\:\mathrm{a}\:\mathrm{square}\:\mathrm{and}\:{M},\:{N}\:\mathrm{points} \\ $$$$\mathrm{on}\:\mathrm{sides}\:{AB},\:{BC}\:\mathrm{respectably},\:\mathrm{such}\:\mathrm{that} \\ $$$$\angle{MDN}\:=\:\mathrm{45}°.\:\mathrm{If}\:{R}\:\mathrm{is}\:\mathrm{the}\:\mathrm{midpoint}\:\mathrm{of} \\ $$$${MN}\:\mathrm{show}\:\mathrm{that}\:{RP}\:=\:{RQ}\:\mathrm{where}\:{P},\:{Q} \\ $$$$\mathrm{are}\:\mathrm{the}\:\mathrm{points}\:\mathrm{of}\:\mathrm{intersection}\:\mathrm{of}\:{AC}\:\mathrm{with} \\ $$$$\mathrm{the}\:\mathrm{lines}\:{MD},\:{ND}. \\ $$ Terms of Service…
Question Number 155701 by ajfour last updated on 03/Oct/21 Commented by ajfour last updated on 03/Oct/21 $${If}\:{the}\:{blue}\:{triangle}\:{is}\:{equilateral} \\ $$$${find}\:{the}\:{radius}\:{ratio}. \\ $$$$\left({the}\:{center}\:{of}\:{both}\:{circles}\:{lie}\:{on}\:{the}\right. \\ $$$$\left.\:\:\:{same}\:{vertical}\right) \\ $$…
Question Number 90161 by I want to learn more last updated on 21/Apr/20 Answered by me2love2math last updated on 21/Apr/20 $${the}\:{square}\:{has}\:{a}\:{larger}\:{perimeter}…. \\ $$$${draw}\:\boldsymbol{{a}}\:\boldsymbol{{chord}}\:\boldsymbol{{that}}\:\boldsymbol{{run}}\:\boldsymbol{{through}}\:\boldsymbol{{the}}\:\boldsymbol{{centre}}\:\boldsymbol{{o}} \\ $$$$\boldsymbol{{centre}}\:\boldsymbol{{of}}\:\boldsymbol{{circle}}\:\boldsymbol{{and}}\:\boldsymbol{{apply}}\:\boldsymbol{{law}}\:\boldsymbol{{of}}\:…
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Question Number 24604 by sastry last updated on 22/Nov/17 $${x}^{\mathrm{2}} −{x}\mathrm{sin}\:{x}−\mathrm{cos}\:{x}=\mathrm{0} \\ $$ Answered by jota last updated on 22/Nov/17 $${Graficando}\:{x}\approx\mathrm{1}.\mathrm{21}\:{o}\:−\mathrm{1}.\mathrm{21} \\ $$ Answered by…
Question Number 155673 by amin96 last updated on 03/Oct/21 Terms of Service Privacy Policy Contact: info@tinkutara.com