Category: Geometry

Question Number 30862 by ajfour last updated on 27/Feb/18 Answered by mrW2 last updated on 27/Feb/18 $$\frac{a}{\sin A}=\frac{b}{\sin B}=\frac{c}{\sin C}=\frac{1}{\lambda }=2R=\frac{abc}{2\sqrt{s(s-a)(s-b)(s-c)}}$$$$\frac{BQ}{\sin (C-\theta )}=\frac{CQ}{\sin \theta }=\frac{BC}{\sin (\pi -\theta -C+\theta )}$$$$\frac{BQ}{\sin (C-\theta )}=\frac{CQ}{\sin \theta }=\frac{a}{\sin C}$$$$\Rightarrow BQ=\frac{\sin (C-\theta )}{\sin C}\times a$$$$\Rightarrow{CQ}=\frac{\mathrm{sin}\:\theta}{\mathrm{sin}\:{C}}×{a}…

Question Number 30808 by 33 last updated on 26/Feb/18 Answered by mrW2 last updated on 26/Feb/18 Commented by mrW2 last updated on 26/Feb/18 $${x}_{\mathrm{1}} =\mathrm{2}{a}\:\mathrm{cos}\:\theta…

Question Number 161742 by mr W last updated on 21/Dec/21 Commented by mr W last updated on 21/Dec/21 $$findtheradiiofthecirclesinside$$$$thebigquatercircle.$$ Answered by…

Question Number 161424 by cherokeesay last updated on 17/Dec/21 Answered by aleks041103 last updated on 17/Dec/21 $${(R-2)}^2+{(R-4)}^2=R^2$$$$R^2-4R+4+R^2-8R+16=R^2$$$${R}^{\mathrm{2}}…

Question Number 95830 by I want to learn more last updated on 27/May/20 Answered by behi83417@gmail.com last updated on 28/May/20 $$\mathrm{4s}+\frac{\mathrm{16}^{\mathrm{2}} }{\mathrm{2}}=\mathrm{16}^{\mathrm{2}} \Rightarrow\mathrm{s}=\frac{\mathrm{16}^{\mathrm{2}} }{\mathrm{8}}=\mathrm{32} \…