Category: Geometry

Question Number 151495 by Tawa11 last updated on 21/Aug/21 Commented by Tawa11 last updated on 21/Aug/21 $$\mathrm{If}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\:\mathrm{square}\:\mathrm{is}\:\:\:\mathrm{144m}^{\mathrm{2}} .\:\:\mathrm{Find}\:\mathrm{the}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circle}. \\ $$$$\mathrm{I}\:\mathrm{got}\:\:\:\:\:\mathrm{6}\sqrt{\mathrm{2}}\:,\:\:\:\:\mathrm{is}\:\mathrm{it}\:\mathrm{correct}? \\ $$ Commented by talminator2856791…

Question Number 151294 by Jonathanwaweh last updated on 19/Aug/21 Answered by ArielVyny last updated on 20/Aug/21 $$\left({a}+{b}+{c}\right)=\mathrm{1}\rightarrow{a}^{\mathrm{2}} +{a}\left({b}+{c}\right)+{b}\left({a}+{c}\right)+{b}^{\mathrm{2}} +{c}^{\mathrm{2}} +{c}\left({b}+{a}\right) \\ $$$${a}^{\mathrm{2}} +{b}^{\mathrm{2}} +{c}^{\mathrm{2}} +\mathrm{2}{ab}+\mathrm{2}{ac}+\mathrm{2}{bc}=\mathrm{1}…

Question Number 20156 by tawa tawa last updated on 22/Aug/17 $$\mathrm{Solve}:\:\mathrm{inverse}\:\mathrm{laplace}.\:\:\:\:\mathrm{L}^{−\mathrm{1}} \left(\frac{\mathrm{s}}{\mathrm{s}^{\mathrm{2}\:} +\:\mathrm{6s}\:+\:\mathrm{25}}\right) \\ $$ Answered by ajfour last updated on 23/Aug/17 $$\mathscr{L}^{−\mathrm{1}} \left(\frac{{s}}{{s}^{\mathrm{2}} +\mathrm{6}{s}+\mathrm{25}}\right)=\mathscr{L}^{−\mathrm{1}}…

Question Number 20131 by NECC last updated on 22/Aug/17 $${In}\:{rectangle}\:{ABCD},{AB}=\mathrm{8}, \\ $$$${BC}=\mathrm{20}.{P}\:{is}\:{a}\:{point}\:{on}\:{AD}\:{so} \\ $$$${that}\:\angle{BPC}=\mathrm{90}°.{If}\:{r}_{\mathrm{1}} ,{r}_{\mathrm{2}} ,{r}_{\mathrm{3}} \:{are}\:{the} \\ $$$${radii}\:{of}\:{the}\:{incircles}\:{of}\:{APB}, \\ $$$${BPC},\:{and}\:{CPD}.\:{find}\:{r}_{\mathrm{1}} +{r}_{\mathrm{2}} +{r}_{\mathrm{3}} \\ $$…

Question Number 85523 by TawaTawa1 last updated on 22/Mar/20 Commented by TawaTawa1 last updated on 22/Mar/20 $$\mathrm{God}\:\mathrm{bless}\:\mathrm{you}\:\mathrm{sir} \\ $$ Answered by MJS last updated on…