Question Number 23796 by tapan das last updated on 06/Nov/17 $$\int\frac{\mathrm{2sinx}+\mathrm{3cosx}}{\mathrm{3sinx}+\mathrm{4cosx}}\:\mathrm{dx} \\ $$ Answered by ajfour last updated on 06/Nov/17 $$\mathrm{2sin}\:{x}+\mathrm{3cos}\:{x}={A}\left(\mathrm{3sin}\:{x}+\mathrm{4cos}\:{x}\right) \\ $$$$\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:+{B}\left(\mathrm{3cos}\:{x}−\mathrm{4sin}\:{x}\right) \\ $$$$\Rightarrow\:\mathrm{3}{A}−\mathrm{4}{B}=\mathrm{2}\:\:{and}…
Question Number 23769 by math solver last updated on 05/Nov/17 $$\mathrm{guys}\:,\:\mathrm{how}\:\mathrm{was}\:\mathrm{kvpy}\:\left(\:\mathrm{SA}\right)?? \\ $$$$:\:\mathrm{tinkutara}\:,\:\mathrm{physicslover},\mathrm{etc}……. \\ $$$$\mathrm{i}\:\mathrm{screwd}\:\mathrm{in}\:\mathrm{bio}\:\mathrm{completely}. \\ $$$$\mathrm{how}\:\mathrm{much}\:\mathrm{you}\:\mathrm{guys}\:\mathrm{are}\:\mathrm{expecting} \\ $$$$\mathrm{and}\:\mathrm{do}\:\mathrm{you}\:\mathrm{have}\:\mathrm{any}\:\mathrm{idea}\:\mathrm{of}\: \\ $$$$\mathrm{cutoff}\:? \\ $$ Commented by…
Question Number 23758 by Anoop kumar last updated on 05/Nov/17 $${solve} \\ $$$$\int\mathrm{tan}^{−\mathrm{1}} {x}\:\mathrm{ln}\:\left(\mathrm{1}+{x}^{\mathrm{2}} \right){dx} \\ $$ Answered by sma3l2996 last updated on 07/Nov/17 Terms…
Question Number 89290 by I want to learn more last updated on 16/Apr/20 Commented by jagoll last updated on 16/Apr/20 $${diagonal}\:=\:\sqrt{\left(\mathrm{14}+\mathrm{9}\right)^{\mathrm{2}} +\mathrm{7}^{\mathrm{2}} } \\ $$$$=\:\sqrt{\mathrm{23}^{\mathrm{2}}…
Question Number 23752 by pombekali last updated on 05/Nov/17 $$\int_{\mathrm{1}} ^{\mathrm{2}} {x}^{\mathrm{3}} +\mathrm{1}=? \\ $$ Answered by Joel577 last updated on 05/Nov/17 $$\left[\frac{\mathrm{1}}{\mathrm{4}}{x}^{\mathrm{4}} \:+\:{x}\right]_{\mathrm{1}} ^{\mathrm{2}}…
Question Number 23679 by math solver last updated on 03/Nov/17 Answered by ajfour last updated on 03/Nov/17 $$\left({B}\right)\:\mathrm{2}:\mathrm{3} \\ $$ Commented by math solver last…
Question Number 23677 by Anoop kumar last updated on 03/Nov/17 $${solve} \\ $$$$\:\:\:\:\:\:\:\:\:\: \\ $$$$\underset{{x}\rightarrow{inf}+} {\mathrm{li}{m}}\:\:\underset{\mathrm{2}{sin}\frac{\mathrm{1}}{{x}}} {\int}^{\mathrm{2}\sqrt{{x}}} \frac{\mathrm{2}{t}^{\mathrm{4}} +\mathrm{1}}{\left({t}−\mathrm{3}\right)\left({t}^{\mathrm{3}} +\mathrm{3}\right)}\:{dt} \\ $$ Terms of Service…
Question Number 23663 by Anoop kumar last updated on 03/Nov/17 $${solve} \\ $$$$ \\ $$$$\underset{−\mathrm{1}} {\int}^{\mathrm{1}_{} } {x}^{\mathrm{2}} {d}\left({lnx}\right) \\ $$$$ \\ $$$$ \\ $$$$…
Question Number 23592 by Tinkutara last updated on 02/Nov/17 $$\mathrm{Let}\:{ABC}\:\mathrm{be}\:\mathrm{a}\:\mathrm{triangle}\:\mathrm{with}\:{AB}\:=\:{AC} \\ $$$$\mathrm{and}\:\angle{BAC}\:=\:\mathrm{30}°.\:\mathrm{Let}\:{A}'\:\mathrm{be}\:\mathrm{the}\:\mathrm{reflection} \\ $$$$\mathrm{of}\:{A}\:\mathrm{in}\:\mathrm{the}\:\mathrm{line}\:{BC};\:{B}'\:\mathrm{be}\:\mathrm{the}\:\mathrm{reflection} \\ $$$$\mathrm{of}\:{B}\:\mathrm{in}\:\mathrm{the}\:\mathrm{line}\:{CA};\:{C}'\:\mathrm{be}\:\mathrm{the}\:\mathrm{reflection} \\ $$$$\mathrm{of}\:{C}\:\mathrm{in}\:\mathrm{the}\:\mathrm{line}\:{AB}.\:\mathrm{Show}\:\mathrm{that}\:{A}',\:{B}',\:{C}' \\ $$$$\mathrm{form}\:\mathrm{the}\:\mathrm{vertices}\:\mathrm{of}\:\mathrm{an}\:\mathrm{equilateral} \\ $$$$\mathrm{triangle}. \\ $$ Answered…
Question Number 89097 by TawaTawa1 last updated on 15/Apr/20 Commented by mr W last updated on 15/Apr/20 $$\sqrt{\mathrm{5}^{\mathrm{2}} +\left(\mathrm{10}+\mathrm{5}\right)^{\mathrm{2}} }=\mathrm{5}\sqrt{\mathrm{10}} \\ $$$${s}=\mathrm{5}\sqrt{\mathrm{10}}−\frac{\mathrm{5}}{\mathrm{5}\sqrt{\mathrm{10}}}\left(\mathrm{15}+\mathrm{5}\right)=\mathrm{3}\sqrt{\mathrm{10}} \\ $$$${area}\:={s}^{\mathrm{2}} =\mathrm{9}×\mathrm{10}=\mathrm{90}…