Question Number 150150 by Tawa11 last updated on 09/Aug/21 Commented by MJS_new last updated on 10/Aug/21 $$\mathrm{6}×\mathrm{6}−\left[\mathrm{4}{quarter}\:{circles}\:{r}=\mathrm{2}\right]−\left[\mathrm{3}{circles}\:{r}=\mathrm{1}\right]= \\ $$$$=\mathrm{36}−\mathrm{7}\pi \\ $$ Commented by Tawa11 last…
Question Number 150136 by Tawa11 last updated on 09/Aug/21 Commented by Tawa11 last updated on 09/Aug/21 $$\mathrm{Thanks}\:\mathrm{sir}.\:\mathrm{God}\:\mathrm{bless}\:\mathrm{you}.\:\mathrm{I}\:\mathrm{appreciate}\:… \\ $$ Answered by mr W last updated…
Question Number 18968 by chux last updated on 02/Aug/17 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{side}\:\mathrm{lengths}\:\mathrm{of}\:\mathrm{a}\:\mathrm{triangle} \\ $$$$\mathrm{if}\:\mathrm{side}\:\mathrm{lengths}\:\mathrm{are}\:\mathrm{consecutive}\: \\ $$$$\mathrm{integers},\mathrm{and}\:\mathrm{one}\:\mathrm{of}\:\mathrm{whose}\:\mathrm{angles} \\ $$$$\mathrm{is}\:\mathrm{twice}\:\mathrm{as}\:\mathrm{large}\:\mathrm{as}\:\mathrm{another}. \\ $$ Commented by chux last updated on 02/Aug/17…
Question Number 18967 by Tinkutara last updated on 02/Aug/17 $$\mathrm{Let}\:\mathrm{PQRS}\:\mathrm{be}\:\mathrm{a}\:\mathrm{rectangle}\:\mathrm{such}\:\mathrm{that} \\ $$$$\mathrm{PQ}\:=\:{a}\:\mathrm{and}\:\mathrm{QR}\:=\:{b}.\:\mathrm{Suppose}\:\mathrm{r}_{\mathrm{1}} \:\mathrm{is}\:\mathrm{the} \\ $$$$\mathrm{radius}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circle}\:\mathrm{passing}\:\mathrm{through}\:\mathrm{P} \\ $$$$\mathrm{and}\:\mathrm{Q}\:\mathrm{and}\:\mathrm{touching}\:\mathrm{RS}\:\mathrm{and}\:\mathrm{r}_{\mathrm{2}} \:\mathrm{is}\:\mathrm{the} \\ $$$$\mathrm{radius}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circle}\:\mathrm{passing}\:\mathrm{through}\:\mathrm{Q} \\ $$$$\mathrm{and}\:\mathrm{R}\:\mathrm{and}\:\mathrm{touching}\:\mathrm{PS}.\:\mathrm{Show}\:\mathrm{that}\:: \\ $$$$\mathrm{5}\left({a}\:+\:{b}\right)\:\leqslant\:\mathrm{8}\left(\mathrm{r}_{\mathrm{1}} \:+\:\mathrm{r}_{\mathrm{2}}…
Question Number 150033 by cherokeesay last updated on 08/Aug/21 Answered by maged last updated on 09/Aug/21 $${A}_{{c}} =\frac{\pi{R}^{\mathrm{2}} }{\mathrm{2}}=\frac{\mathrm{36}\pi}{\mathrm{2}}=\mathrm{18}\pi \\ $$$$\mid{BH}\mid={R}\mathrm{sin}\:\mathrm{60}°=\mathrm{6}×\frac{\sqrt{\mathrm{3}}}{\mathrm{2}}=\mathrm{3}\sqrt{\mathrm{3}} \\ $$$${A}_{{y}} ={A}_{{s}} +{A}_{{t}}…
Question Number 84409 by mr W last updated on 12/Mar/20 Commented by mr W last updated on 12/Mar/20 $${Find}\:{the}\:{radius}\:{r}. \\ $$ Commented by ajfour last…
Question Number 149940 by ajfour last updated on 08/Aug/21 Commented by ajfour last updated on 08/Aug/21 $${see}\:{Q}.\mathrm{149894} \\ $$ Answered by ajfour last updated on…
Question Number 84381 by behi83417@gmail.com last updated on 12/Mar/20 Commented by behi83417@gmail.com last updated on 12/Mar/20 $$\mathrm{AB}=\mathrm{9},\mathrm{BC}=\mathrm{10},\mathrm{CA}=\mathrm{12} \\ $$$$\mathrm{FI},\mathrm{divides}\:\mathrm{triangle}\:\mathrm{in}\:\mathrm{two}\:\mathrm{parts}\:\mathrm{that}\:\mathrm{equail}\:\mathrm{in}\: \\ $$$$\mathrm{area}\:\mathrm{and}\:\mathrm{perimeter}. \\ $$$$\mathrm{find}:\mathrm{CI},\mathrm{CF},\mathrm{FI}. \\ $$…
Question Number 149894 by ajfour last updated on 08/Aug/21 Commented by ajfour last updated on 08/Aug/21 $${Find}\:{minimum}\:{and}\:{maximum} \\ $$$${values}\:{for}\:{the}\:{side}\:{of}\:{equilateral} \\ $$$${triangle}\:{shown}. \\ $$ Answered by…
Question Number 18801 by behi.8.3.4.1.7@gmail.com last updated on 30/Jul/17 Commented by behi.8.3.4.1.7@gmail.com last updated on 30/Jul/17 $${AB}=\mathrm{10},{AC}=\mathrm{12},{BC}=\mathrm{16} \\ $$$${connect}\:{foot}\:{of}\:{altitudes}\:{to}\:{make}\:{black} \\ $$$${triangles}\:{and}\:{do}\:{this}\:{in}\:{next}\:{triangles}, \\ $$$${as}\:{shown}. \\ $$$${find}\:{the}\:{area}\:{of}\:{last}\:{small}\:{black}\:{triangle}.…