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Question Number 18461 by b.e.h.i.8.3.417@gmail.com last updated on 22/Jul/17 Answered by mrW1 last updated on 22/Jul/17 $$\left.\mathrm{1}\right) \\ $$$$\Delta_{\mathrm{AA}_{\mathrm{5B}} \mathrm{A}_{\mathrm{60C}} } =\frac{\mathrm{5}}{\mathrm{n}}×\frac{\mathrm{60}}{\mathrm{n}}×\Delta_{\mathrm{ABC}} \\ $$$$\Delta_{\mathrm{BCC}_{\mathrm{5A}} }…
Question Number 149510 by Tawa11 last updated on 05/Aug/21 Commented by Ar Brandon last updated on 06/Aug/21 $$\mathrm{36}−\mathrm{4}×\frac{\mathrm{9}}{\mathrm{2}}=\mathrm{18cm}^{\mathrm{3}} \\ $$ Commented by Tawa11 last updated…
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Question Number 149068 by Tawa11 last updated on 02/Aug/21 Answered by mr W last updated on 03/Aug/21 Commented by mr W last updated on 02/Aug/21…