Category: Geometry

Question Number 23592 by Tinkutara last updated on 02/Nov/17 $$\mathrm{Let}ABC\mathrm{be}\mathrm{a}\mathrm{triangle}\mathrm{with}AB=AC$$$$\mathrm{and}\mathrm{\angle }BAC=30°.\mathrm{Let}{A}^{\prime }\mathrm{be}\mathrm{the}\mathrm{reflection}$$$$\mathrm{of}A\mathrm{in}\mathrm{the}\mathrm{line}BC;B^{\prime }\mathrm{be}\mathrm{the}\mathrm{reflection}$$$$\mathrm{of}B\mathrm{in}\mathrm{the}\mathrm{line}CA;C^{\prime }\mathrm{be}\mathrm{the}\mathrm{reflection}$$$$\mathrm{of}C\mathrm{in}\mathrm{the}\mathrm{line}AB.\mathrm{Show}\mathrm{that}{A}^{\prime },B^{\prime },C^{\prime }$$$$\mathrm{form}\mathrm{the}\mathrm{vertices}\mathrm{of}\mathrm{an}\mathrm{equilateral}$$$$\mathrm{triangle}.$$ Answered…

Question Number 23539 by tapan das last updated on 01/Nov/17 $$\int \tan {}^6\mathrm{x}\mathrm{dx}$$ Answered by $@ty@mlastupdatedon01/Nov/17$$\int\mathrm{tan}\:^{\mathrm{4}} {x}\left(\mathrm{sec}\:^{\mathrm{2}} {x}−\mathrm{1}\right){dx} \…

Question Number 23477 by kami last updated on 31/Oct/17 $$\mathrm{Find}\mathrm{the}\mathrm{value}\mathrm{of}x,$$$${\int }_{-\mathrm{\infty }}^{x}d\mathrm{x}=\int \mid \pm \sinh \cot \ln (15-\sqrt{33+x})\mid \mathrm{dx}$$ Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 23408 by selestian last updated on 29/Oct/17 Answered by mrW1 last updated on 31/Oct/17 $$\mathrm{FE}=\frac{5}{10}\times 18=9$$$$\mathrm{AC}=\frac{15}{9}\times (5+10)=25$$$$\Rightarrow \mathrm{Answer}\left(\mathrm{b}\right)$$ Terms of…

Question Number 88933 by TawaTawa1 last updated on 13/Apr/20 Commented by john santu last updated on 14/Apr/20 $${30}^o$$ Commented by mr W last…