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Category: Geometry

Question-205892

Question Number 205892 by cortano12 last updated on 02/Apr/24 Answered by A5T last updated on 02/Apr/24 Commented by A5T last updated on 02/Apr/24 $${AC}={ytan}\left(\mathrm{3}\alpha\right);{x}={ytan}\alpha;{z}=\frac{{y}}{{cos}\alpha};{c}={y}\left({tan}\mathrm{3}\alpha−{tan}\alpha\right) \\…