Category: Geometry

Question Number 85523 by TawaTawa1 last updated on 22/Mar/20 Commented by TawaTawa1 last updated on 22/Mar/20 $$\mathrm{God}\mathrm{bless}\mathrm{you}\mathrm{sir}$$ Answered by MJS last updated on…

Question Number 85447 by TawaTawa1 last updated on 22/Mar/20 Commented by TawaTawa1 last updated on 22/Mar/20 $$\mathrm{Please}\mathrm{workings}$$ Commented by john santu last updated…

Question Number 85364 by Power last updated on 21/Mar/20 Commented by Power last updated on 21/Mar/20 $$$$ Commented by Power last updated on…

Question Number 19792 by Tinkutara last updated on 15/Aug/17 $$\mathrm{Let}ABCD\mathrm{be}\mathrm{a}\mathrm{convex}\mathrm{quadrilateral}$$$$\mathrm{with}\mathrm{\angle }DAB=\mathrm{\angle }BDC=90°.\mathrm{Let}\mathrm{the}$$$$\mathrm{incircles}\mathrm{of}\mathrm{triangles}ABD\mathrm{and}BCD$$$$\mathrm{touch}BD\mathrm{at}P\mathrm{and}Q,\mathrm{respectively},$$$$\mathrm{with}P\mathrm{lying}\mathrm{in}\mathrm{between}B\mathrm{and}Q.\mathrm{If}$$$$AD=999\mathrm{and}PQ=200\mathrm{then}\mathrm{what}\mathrm{is}$$$$\mathrm{the}\mathrm{sum}\mathrm{of}\mathrm{the}\mathrm{radii}\mathrm{of}\mathrm{the}\mathrm{incircles}\mathrm{of}$$$$\mathrm{triangles}\:{ABD}\:\mathrm{and}\:{BDC}? \…

Question Number 19783 by NECC last updated on 15/Aug/17 $$Thesidesofatriangleareof$$$$lengths\sqrt{(m^2-n^2)},m^2+n^2,2mn.$$$$Showthatitisarightangle\mathrm{\Delta }.$$ Commented by Tinkutara last updated…