Question Number 82131 by mr W last updated on 18/Feb/20 Commented by ajfour last updated on 18/Feb/20 Commented by mr W last updated on 18/Feb/20…
Question Number 16595 by ajfour last updated on 24/Jun/17 Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 25/Jun/17 $${you}\:{are}\:{wellcome}\:{dear}\:{mr}\:{Ajfour}.{please}\: \\ $$$${post}\:{your}\:{answer}.{i}\:{am}\:{waiting}\:{for}\:{it}. \\ $$ Commented by ajfour last…
Question Number 16592 by chux last updated on 24/Jun/17 $$\mathrm{please}\:\mathrm{what}\:\mathrm{does}\:\mathrm{the}\:\mathrm{question}\:\mathrm{mean} \\ $$$$\mathrm{by}\:\mathrm{the}\:\mathrm{overlapping}\:\mathrm{portion}\:\mathrm{of}\:\mathrm{A}\: \\ $$$$\mathrm{and}\:\mathrm{B}. \\ $$ Commented by chux last updated on 24/Jun/17 Answered by…
Question Number 16579 by Joel577 last updated on 24/Jun/17 Commented by Joel577 last updated on 24/Jun/17 $$\mathrm{Mr}.\:\mathrm{Ajfour},\:\mathrm{why}\:\angle{P}\:\:\mathrm{is}\:\mathrm{2}\theta? \\ $$ Commented by Joel577 last updated on…
Question Number 16570 by chux last updated on 24/Jun/17 $$\mathrm{A},\mathrm{B}\:\mathrm{and}\:\mathrm{E}\:\mathrm{are}\:\mathrm{three}\:\mathrm{circles}\:\mathrm{all}\: \\ $$$$\mathrm{with}\:\mathrm{radius}\:\mathrm{1}\:\mathrm{unit}.\mathrm{A}\:\mathrm{and}\:\mathrm{E}\:\mathrm{touch} \\ $$$$\mathrm{at}\:\mathrm{P}\:\mathrm{whole}\:\mathrm{B}\:\mathrm{and}\:\mathrm{E}\:\mathrm{touch}\:\mathrm{at}\:\mathrm{Q}. \\ $$$$\angle\mathrm{POQ}=\mathrm{x}°\:\mathrm{where}\:\mathrm{O}\:\mathrm{is}\:\mathrm{the}\:\mathrm{centre}\: \\ $$$$\mathrm{of}\:\mathrm{E}.\mathrm{Find}\:\mathrm{the}\:\mathrm{area}\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{overlapping}\:\mathrm{portion}\:\mathrm{of}\:\mathrm{A}\:\mathrm{and}\:\mathrm{B}\:\mathrm{if} \\ $$$$\mathrm{0}\leqslant\mathrm{x}\leqslant\mathrm{60}° \\ $$ Commented…
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Question Number 147606 by vvvv last updated on 22/Jul/21 $$\frac{\boldsymbol{\mathrm{R}}}{\boldsymbol{{r}}}=\frac{\mathrm{5}}{\mathrm{2}}\:\:\Rightarrow\:\boldsymbol{{a}}:\boldsymbol{{b}}:\boldsymbol{{c}}=\mathrm{3}:\mathrm{4}:\mathrm{5} \\ $$$$\boldsymbol{\mathrm{prove}}\:\: \\ $$$$\boldsymbol{\mathrm{R}},\boldsymbol{{r}}−\:\boldsymbol{\mathrm{radius}} \\ $$$$\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{a}}} :\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{b}}} :\boldsymbol{\mathrm{h}}_{\boldsymbol{\mathrm{c}}} =\frac{\mathrm{1}}{\boldsymbol{{a}}}:\frac{\mathrm{1}}{\boldsymbol{{b}}}:\frac{\mathrm{1}}{\boldsymbol{{c}}}=\boldsymbol{{bc}}:\boldsymbol{{ac}}:\boldsymbol{{ab}} \\ $$$$\boldsymbol{{prove}} \\ $$ Terms of…
Question Number 82042 by ajfour last updated on 17/Feb/20 Commented by ajfour last updated on 17/Feb/20 $${Find}\:{ratio}\:{of}\:{side}\:{lengths}\:{of} \\ $$$${outer}\:{equilateral}\:\bigtriangleup{KLM}\:{to} \\ $$$${that}\:{of}\:{inner}\:{equilateral}\:\bigtriangleup{PQR}. \\ $$ Commented by…
Question Number 147561 by vvvv last updated on 21/Jul/21 Commented by vvvv last updated on 21/Jul/21 $$\boldsymbol{{prove}} \\ $$ Answered by mr W last updated…
Question Number 16483 by RasheedSoomro last updated on 23/Jun/17 Commented by RasheedSoomro last updated on 23/Jun/17 $$\mathrm{Thanks}\:\mathrm{sir}\:\mathrm{for}\:\mathrm{mentioning}\:\mathrm{mistake}. \\ $$$$\mathrm{The}\:\mathrm{figure}\:\mathrm{has}\:\mathrm{been}\:\mathrm{changed}. \\ $$ Commented by RasheedSoomro last…