Menu Close

Category: Geometry

Question-15700

Question Number 15700 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 12/Jun/17 Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 13/Jun/17 $${j},{is}\:{the}\:{incircle}\:{of}\:{A}\overset{\Delta} {{B}C}. \\ $$$${MN}\parallel{AC},{KL}\parallel{AB},{OP}\parallel{BC} \\ $$$${OP}={x},{MN}={y},{KL}={z},{AB}={c},{BC}={a},{AC}={b}. \\ $$$${a}>{b}>{c}>\mathrm{1} \\…

3-5x-58-

Question Number 15699 by zildabatistoti last updated on 12/Jun/17 $$\mathrm{3}+\mathrm{5x}=\mathrm{58} \\ $$ Answered by Joel577 last updated on 13/Jun/17 $$\mathrm{5}{x}\:=\:\mathrm{58}\:−\:\mathrm{3}\:=\:\mathrm{55} \\ $$$${x}\:=\:\frac{\mathrm{55}}{\mathrm{5}}\:=\:\mathrm{11} \\ $$ Terms…

Question-15642

Question Number 15642 by mrW1 last updated on 12/Jun/17 Answered by ajfour last updated on 12/Jun/17 $$\:\:{Required}\:{Area}={S} \\ $$$$\:{let}\:{O}\:{be}\:{origin}. \\ $$$$\:{A}\left({a},\mathrm{0}\right)\:;\:{B}\left(\mathrm{0},{b}\right)\:;\:{C}\left(−{c},\mathrm{0}\right)\:; \\ $$$$\:{D}\left(\mathrm{0},−{d}\right)\:;\:{E}\left({a}+{p},\:−{d}−{q}\right) \\ $$$$\:\:\frac{{q}+{d}}{{p}}=\frac{{b}}{{a}}\:\:\:,\:\:\:\:\:\frac{{p}+{a}}{{q}}=\frac{{c}}{{d}}…

Question-81122

Question Number 81122 by mr W last updated on 09/Feb/20 Commented by mr W last updated on 09/Feb/20 $${black}\:{dot}\:{is}\:{the}\:{center}\:{of}\:{circle}. \\ $$$${both}\:{angles}\:{marked}\:{with}\:“\mathrm{o}''\:{are}\:{equal}. \\ $$$${two}\:{lengthes}\:{are}\:{given}:\:\mathrm{5}\:{and}\:\mathrm{6}. \\ $$$${find}\:{length}\:{x}=?…

Question-15572

Question Number 15572 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 12/Jun/17 Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 12/Jun/17 $${circle}\::{c}\:{tangent}\:{to}\:{semicircle}\:{AEB}\:{at}: \\ $$$${points}:\:{E}\:\&\:{D}.\:{AD}={a}=\mathrm{12},{DB}={b}=\mathrm{5}. \\ $$$$……………………………………………. \\ $$$$\left.\mathrm{1}\right){DE}={x}=?,{AE}=? \\ $$$$\left.\mathrm{2}\right)\:\:{show}\:{that}:\:\:\measuredangle{AED}=\mathrm{45}^{\bullet}…

Question-15567

Question Number 15567 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 11/Jun/17 Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 11/Jun/17 $${ABCD}\:\&\:{MNPQ},{are}\:{squares}. \\ $$$${show}\:{that}: \\ $$$${a}^{\mathrm{2}} +{b}^{\mathrm{2}} ={c}^{\mathrm{2}} +{d}^{\mathrm{2}} \\…