Question Number 15175 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 08/Jun/17 Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 08/Jun/17 $${in}\:{triangle}\:{ABC}: \\ $$$${BC}=\mathrm{13},{AB}=\mathrm{14},{AC}=\mathrm{15} \\ $$$${DJ},{is}\:{the}\:{perpendicular}\:{bisector}\:{of}\:{AC}. \\ $$$${DI}\bot{BC}. \\ $$$$………………………
Question Number 15170 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 07/Jun/17 Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 07/Jun/17 $${ABCD},{is}\:{a}\:{square}\:{with}\:{area}=\mathrm{1} \\ $$$${each}\:{acute}\:{angles}\:{such}\:{that}:\measuredangle{ADA}' \\ $$$${are}\:{equail}\:{to}:\mathrm{15}^{\bullet} \\ $$$$\left.\mathrm{1}\right){show}\:{that}\::{the}\:{white}\:{shape}\:{is}\:{a}\:{square}. \\ $$$$\left.\mathrm{2}\right){find}\:{it}'{s}\:{area}.…
Question Number 80682 by ajfour last updated on 05/Feb/20 Commented by ajfour last updated on 05/Feb/20 $${If}\:{both}\:{coloured}\:{areas}\:{are}\:{equal}, \\ $$$${find}\:{r}. \\ $$ Commented by ajfour last…
Question Number 80587 by ajfour last updated on 04/Feb/20 Commented by ajfour last updated on 04/Feb/20 $${Given}:\:\bigtriangleup{ABC}\:{is}\:{equilateral}, \\ $$$${radius}\:{of}\:{small}\:{circle}\:{is}\:\mathrm{1}. \\ $$$${Find}\:{radius}\:{of}\:{outer}\:{circle},\:{a}. \\ $$ Commented by…
Question Number 80574 by ajfour last updated on 04/Feb/20 Commented by ajfour last updated on 04/Feb/20 $${Both}\:{circles}\:{have}\:{equal}\:{radius}; \\ $$$${Find}\:\alpha. \\ $$ Commented by ajfour last…
Question Number 15017 by tawa tawa last updated on 06/Jun/17 $$\mathrm{Calculate}\:\mathrm{the}\:\mathrm{heat}\:\mathrm{neccessary}\:\mathrm{to}\:\mathrm{raise}\:\mathrm{the}\:\mathrm{temperature}\:\mathrm{of}\:\mathrm{5}.\mathrm{00}\:\mathrm{mol}\:\mathrm{of}\:\mathrm{butane} \\ $$$$\mathrm{from}\:\mathrm{290K}\:\mathrm{to}\:\mathrm{593K}\:\mathrm{at}\:\mathrm{a}\:\mathrm{constant}\:\mathrm{pressure}.\:\mathrm{where}\:\mathrm{Cp}\left(\mathrm{19}.\mathrm{41}\:+\:\mathrm{0}.\mathrm{233T}\right)\mathrm{J}/\mathrm{mol}/\mathrm{K} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 80539 by lalitchand last updated on 04/Feb/20 Commented by mr W last updated on 04/Feb/20 $${insufficient}\:{condition}!\:{P}\:{and}\:{R} \\ $$$${can}\:{be}\:{everywhere}. \\ $$ Terms of Service…
Question Number 146048 by ArielVyny last updated on 10/Jul/21 $${in}\:{a}\:{triangle}\:{ABC}\:\:{we}\:{have}\: \\ $$$$\begin{cases}{\mathrm{3}{sin}\hat {{A}}+\mathrm{4}{cos}\hat {{B}}=\mathrm{6}}\\{\mathrm{4}{sin}\hat {{B}}+\mathrm{3}{cos}\hat {{A}}=\mathrm{1}}\end{cases} \\ $$$${find}\:\hat {{C}} \\ $$$$ \\ $$ Answered by…
Question Number 14965 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 06/Jun/17 Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 06/Jun/17 $${in}\:{triangle}\:{ABD}: \\ $$$${CF},{IH},{GJ},{are}\:{the}\:{perpendicular}\: \\ $$$${bisector}\:{of}\:{sides}. \\ $$$${AD}=\mathrm{12},{AB}=\mathrm{14},{BD}=\mathrm{16} \\ $$$$……………\sqrt{…….}….===\sqrt{……..}…=…..…
Question Number 14964 by alifhijriah last updated on 06/Jun/17 $$\mathrm{proof}\:\mathrm{that}\: \\ $$$$\forall\:{x},{y}\:\in\mathbb{N}\:\:\exists\:{a},{b},{c}\:\in\mathbb{N}\:\backepsilon\:\frac{\mathrm{4}}{{x}^{\mathrm{2}} +{y}^{\mathrm{2}} }=\frac{\mathrm{1}}{{a}}\:+\:\frac{\mathrm{1}}{{b}}\:+\:\frac{\mathrm{1}}{{c}} \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com