Category: Geometry

Question Number 13127 by Madhuri Dixit last updated on 15/May/17 Terms of Service Privacy Policy Contact: info@tinkutara.com

Question Number 13067 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 13/May/17 Commented by b.e.h.i.8.3.4.1.7@gmail.com last updated on 13/May/17 $${in}\:{triangle}\:{ABC}: \\ $$$$\left.{i}\right)\:\:\:\:\:\:\:\measuredangle{BIA}=\measuredangle{CIB}=\measuredangle{AIC} \\ $$$$\left.{ii}\right)\:\:\:\:{DE}\bot{BC},{DF}\bot{AC},{DH}\bot{AB} \\ $$$$\left.{iii}\right)\:\:\:{S}_{{ABC}} =\:\:\mathrm{1}\:\:\left({area}\:{of}\:\Delta{ABC}\right) \\…

Question Number 131463 by bramlexs22 last updated on 05/Feb/21 Commented by mr W last updated on 05/Feb/21 $$\left(\mathrm{0},\pm\mathrm{1}\right) \\ $$ Terms of Service Privacy Policy…

Question Number 374 by novrya last updated on 25/Jan/15 $${S}\mathrm{how}\:\mathrm{that} \\ $$$$\mathrm{the}\:\mathrm{function}\:{f}\left({x}\right)=\sqrt{{x}}\:\mathrm{continuous}\:\mathrm{on}\:\left[\mathrm{0},\infty\right) \\ $$ Answered by prakash jain last updated on 25/Dec/14 $$\mathrm{Right}\:\mathrm{Hand}\:\mathrm{Limit}=\mathrm{Left}\:\mathrm{Hand}\:\mathrm{Limit}=\mathrm{Value} \\ $$$$\underset{{h}\rightarrow\mathrm{0}}…

Question Number 364 by novrya last updated on 25/Jan/15 $${li}\underset{{n}\rightarrow\infty} {{m}}\left[\frac{{f}\left({a}+\mathrm{1}/{n}\right)}{{f}\left({a}\right)}\right]^{{n}} =…. \\ $$ Answered by prakash jain last updated on 24/Dec/14 $${y}=\left[\frac{{f}\left({a}+\mathrm{1}/{x}\right)}{{f}\left({a}\right)}\right]^{{x}} \\ $$$$\mathrm{ln}\:{y}={x}\left[\mathrm{ln}{f}\left({a}+\frac{\mathrm{1}}{{x}}\right)−\mathrm{ln}\:{f}\left({a}\right)\right]…