Category: Geometry

Question Number 81755 by Power last updated on 15/Feb/20 Answered by mr W last updated on 15/Feb/20 Commented by mr W last updated on 15/Feb/20…

Question Number 16194 by RasheedSoomro last updated on 18/Jun/17 Commented by RasheedSoomro last updated on 18/Jun/17 $$\mathrm{A},\mathrm{B}\mathrm{and}\mathrm{C}\mathrm{are}\mathrm{three}\mathrm{non}-\mathrm{collinear}\mathrm{points}.$$$$\mathrm{Also}\mathrm{they}\mathrm{are}\mathrm{centers}\mathrm{of}\mathrm{three}\mathrm{circles}\mathrm{having}$$$$\mathrm{radii}a,b\mathrm{and}c\mathrm{respectively}.\mathrm{D},\mathrm{E}\mathrm{\&}\mathrm{F}\mathrm{have}\mathrm{been}$$$$\mathrm{taken}\mathrm{on}\mathrm{three}\mathrm{circles}\mathrm{respectively}\mathrm{in}\mathrm{such}\mathrm{a}\mathrm{way}$$$$\mathrm{that}\:\bigtriangleup\mathrm{DEF}\:\mathrm{is}\:\mathrm{an}\:\mathrm{equilateral}\:\mathrm{triangle}.…

Question Number 147229 by Tawa11 last updated on 19/Jul/21 Answered by Olaf_Thorendsen last updated on 19/Jul/21 $$2\times ({42}^2-\frac{1}{4}\times \pi \times {42}^2)=882(4-\pi )$$ Commented by Tawa11 last…

Question Number 81649 by Power last updated on 14/Feb/20 Commented by Power last updated on 14/Feb/20 $$\mathrm{BDM}\mathrm{triangular}\mathrm{face}-?$$ Commented by Power last updated on…

Question Number 16108 by Joel577 last updated on 18/Jun/17 Commented by Joel577 last updated on 18/Jun/17 $$\mathrm{How}\mathrm{to}\mathrm{find}\mathrm{\angle }PAD?$$ Answered by ajfour last updated on…