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Category: Geometry

Question-78056

Question Number 78056 by ajfour last updated on 13/Jan/20 Answered by ajfour last updated on 13/Jan/20 $${It}\:{is}\:{from}\:{aid}\:{of}\:{another} \\ $$$${diagram}\:{that}\:{x}^{\mathrm{3}} −{x}=\mathrm{2}{c}\:\:\:\:….\left({i}\right) \\ $$$${From}\:{here} \\ $$$${first}\:{let}\:{AH}={r} \\…

A-wooden-stick-was-broken-randomly-into-three-pieces-What-is-the-probability-that-a-triangle-can-be-built-from-those-three-parts-

Question Number 12506 by Joel577 last updated on 24/Apr/17 $$\mathrm{A}\:\mathrm{wooden}\:\mathrm{stick}\:\mathrm{was}\:\mathrm{broken}\:\mathrm{randomly}\:\mathrm{into} \\ $$$$\mathrm{three}\:\mathrm{pieces}.\:\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{probability}\:\mathrm{that}\:\mathrm{a}\:\mathrm{triangle} \\ $$$$\mathrm{can}\:\mathrm{be}\:\mathrm{built}\:\mathrm{from}\:\mathrm{those}\:\mathrm{three}\:\mathrm{parts}? \\ $$ Answered by mrW1 last updated on 25/Apr/17 $${Let}'{s}\:{say}\:{the}\:{wooden}\:{stick}\:{is}\:{brocken}\: \\…

Water-flows-out-of-a-tank-through-a-hole-of-diameter-2cm-above-the-hole-1-Determine-the-velocity-of-outflow-2-The-rate-of-outflow-when-the-level-of-the-water-in-the-tank-is-2cm-above-the-hole-

Question Number 12499 by tawa last updated on 23/Apr/17 $$\mathrm{Water}\:\mathrm{flows}\:\mathrm{out}\:\mathrm{of}\:\mathrm{a}\:\mathrm{tank}\:\mathrm{through}\:\mathrm{a}\:\mathrm{hole}\:\mathrm{of}\:\mathrm{diameter}\:\mathrm{2cm}\:\mathrm{above}\:\mathrm{the}\:\mathrm{hole} \\ $$$$\left(\mathrm{1}\right)\:\mathrm{Determine}\:\mathrm{the}\:\mathrm{velocity}\:\mathrm{of}\:\mathrm{outflow} \\ $$$$\left(\mathrm{2}\right)\:\mathrm{The}\:\mathrm{rate}\:\mathrm{of}\:\mathrm{outflow}\:\mathrm{when}\:\mathrm{the}\:\mathrm{level}\:\mathrm{of}\:\mathrm{the}\:\mathrm{water}\:\mathrm{in}\:\mathrm{the}\:\mathrm{tank}\:\mathrm{is}\:\mathrm{2cm}\:\mathrm{above} \\ $$$$\mathrm{the}\:\mathrm{hole}.\: \\ $$ Answered by sandy_suhendra last updated on 24/Apr/17…

Question-77966

Question Number 77966 by mr W last updated on 12/Jan/20 Answered by john santu last updated on 12/Jan/20 $${ratio}\:{area}\:=\:\mathrm{4}\::\:\mathrm{9}\::\:\mathrm{49}\: \\ $$$${ratio}\:{of}\:{side}\:=\:\mathrm{2}:\mathrm{3}:\mathrm{7} \\ $$$${area}\:{ABC}\:=\:\mathrm{36}×\mathrm{4}\:=\:\mathrm{144} \\ $$…