Question Number 142560 by ajfour last updated on 02/Jun/21 Answered by 1549442205PVT last updated on 02/Jun/21 $$\mathrm{put}\:\mathrm{AC}=\mathrm{x},\mathrm{CP}=\mathrm{y}\Rightarrow\mathrm{AO}.\mathrm{OB}=\mathrm{OP}^{\mathrm{2}} \\ $$$$\Leftrightarrow\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{c}^{\mathrm{2}} }\left(\mathrm{1}−\sqrt{\mathrm{c}^{\mathrm{2}} +\mathrm{x}^{\mathrm{2}} }\right)=\mathrm{c}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} \left(\mathrm{1}\right)…
Question Number 77026 by TawaTawa last updated on 02/Jan/20 Commented by $@ty@m123 last updated on 03/Jan/20 $${Which}\:{one}? \\ $$$$\mathrm{20}\:{or}\:\mathrm{21} \\ $$ Commented by TawaTawa last…
Question Number 142546 by cesarL last updated on 02/Jun/21 $${i}\:{need}\:{help} \\ $$ Commented by cesarL last updated on 02/Jun/21 Terms of Service Privacy Policy Contact:…
Question Number 76948 by Master last updated on 01/Jan/20 Answered by mr W last updated on 02/Jan/20 $${let}\:\alpha=\angle{A} \\ $$$$\angle{B}=\frac{\pi}{\mathrm{2}}−\frac{\alpha}{\mathrm{2}} \\ $$$${AB}={AC}=\frac{\mathrm{1}}{\mathrm{2}\:\mathrm{sin}\:\frac{\alpha}{\mathrm{2}}} \\ $$$$\left(\sqrt{\mathrm{2}}\right)^{\mathrm{2}} =\mathrm{1}^{\mathrm{2}}…
Question Number 11403 by JAZAR last updated on 24/Mar/17 $${how}\:{can}\:{demonstred}\:{that}\: \\ $$$${cos}\left(\mathrm{2}{x}\right)−{sin}\left(\mathrm{2}{x}\right)−\mathrm{1}=−{cos}^{\mathrm{2}} {x} \\ $$ Commented by sm3l2996 last updated on 24/Mar/17 $$\mathrm{I}\:\mathrm{think}\:\mathrm{that}\:\mathrm{equation}\:\mathrm{is}\:\mathrm{not}\:\mathrm{correct} \\ $$$$\mathrm{because}\:\mathrm{cos}\left(\mathrm{2}\pi\right)−\mathrm{sin}\left(\mathrm{2}\pi\right)−\mathrm{1}=\mathrm{0}\neq−\mathrm{cos}^{\mathrm{2}}…
Question Number 11343 by jaskaurrangerleader@gmail.com last updated on 21/Mar/17 $${n}_{\boldsymbol{\mathrm{c}}_{\boldsymbol{\mathrm{n}}} } =\frac{{n}\mathrm{1}}{\left({n}−{n}\right)} \\ $$ Commented by FilupS last updated on 21/Mar/17 $$\frac{{n}}{{n}−{n}}=\mathrm{undefined} \\ $$ Terms…
Question Number 11344 by jaskaurrangerleader@gmail.com last updated on 21/Mar/17 $${n}_{{c}_{{n}} } =\frac{{n}!}{\left({n}−{n}\right)!{n}!} \\ $$ Commented by FilupS last updated on 21/Mar/17 $$\frac{{n}!}{\left({n}−{n}\right)!\centerdot{n}!}=\frac{\mathrm{1}}{\mathrm{0}!} \\ $$$$=\frac{\mathrm{1}}{\mathrm{1}}=\mathrm{1} \\…
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Question Number 11221 by b.e.h.i.8.3.4.1.7@gmail.com last updated on 17/Mar/17 Commented by mrW1 last updated on 18/Mar/17 $${center}\:{point}\:{of}\:{the}\:{circle}\:{M}\left({a},{a}\right) \\ $$$${radius}\:{of}\:{the}\:{circle}\:{R}=\left({a}−\mathrm{1}\right)\sqrt{\mathrm{2}} \\ $$$$\mathrm{sin}\:\frac{\theta}{\mathrm{2}}=\frac{{R}}{{a}\sqrt{\mathrm{2}}}=\mid\frac{{a}−\mathrm{1}}{{a}}\mid\leqslant\mathrm{1} \\ $$$$\theta=\mathrm{2sin}^{−\mathrm{1}} \left(\mid\frac{{a}−\mathrm{1}}{{a}}\mid\right),\:\mid{a}\mid\geqslant\frac{\mathrm{1}}{\mathrm{2}} \\…
Question Number 142282 by pete last updated on 29/May/21 $$\mathrm{Three}\:\mathrm{interior}\:\mathrm{angles}\:\mathrm{of}\:\mathrm{a}\:\mathrm{polygon}\:\mathrm{are}\:\mathrm{160}° \\ $$$$\mathrm{each}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{other}\:\mathrm{interior}\:\mathrm{angles}\:\mathrm{are}\:\mathrm{120}°\:\mathrm{each}, \\ $$$$\mathrm{find}\:\mathrm{the}\:\mathrm{number}\:\mathrm{of}\:\mathrm{sides}\:\mathrm{of}\:\mathrm{the}\:\mathrm{polygon}. \\ $$ Answered by som(math1967) last updated on 29/May/21 $$\boldsymbol{{let}}\:\boldsymbol{{no}}\:\boldsymbol{{of}}\:\boldsymbol{{sides}}=\boldsymbol{{n}} \\…