Question Number 11183 by Nayon last updated on 15/Mar/17 Answered by mrW1 last updated on 16/Mar/17 $${let}\:{x}=\frac{{AD}}{{AB}} \\ $$$$\Rightarrow{DE}={x}×{BC} \\ $$$${a}={ABC}=\frac{\mathrm{1}}{\mathrm{2}}×{BC}×{h} \\ $$$${ADC}=\frac{\mathrm{1}}{\mathrm{2}}×{DE}×{h}=\frac{\mathrm{1}}{\mathrm{2}}×{x}×{BC}×{h}={xa} \\ $$$${ADE}=\frac{\mathrm{1}}{\mathrm{2}}×{DE}×{x}×{h}=\frac{\mathrm{1}}{\mathrm{2}}×{x}×{BC}×{x}×{h}={x}^{\mathrm{2}}…
Question Number 11148 by suci last updated on 14/Mar/17 $$\int\frac{{x}\:{dx}}{\:\sqrt[{\mathrm{3}}]{{x}+\mathrm{1}}}=….??? \\ $$ Answered by ajfour last updated on 14/Mar/17 $$=\:\frac{\mathrm{3}\left({x}+\mathrm{1}\right)^{\mathrm{5}/\mathrm{3}} }{\mathrm{5}}\:−\frac{\mathrm{3}\left({x}+\mathrm{1}\right)^{\mathrm{2}/\mathrm{3}} }{\mathrm{2}}\:+{C}\: \\ $$ Commented…
Question Number 142218 by Dwaipayan Shikari last updated on 27/May/21 $${Straight}\:{line}\:{lx}+{my}=\mathrm{1}\:\:{is}\:{tangent}\:{to}\:{the}\:{curve}\:\left({ax}\right)^{{n}} +\left({by}\right)^{{n}} =\mathrm{1} \\ $$$${Prove}\:{that}\:\left(\frac{{l}}{{a}}\right)^{\frac{{n}}{{n}−\mathrm{1}}} +\left(\frac{{m}}{{b}}\right)^{\frac{{n}}{{n}−\mathrm{1}}} =\mathrm{1} \\ $$ Answered by som(math1967) last updated on…
Question Number 142164 by Panacea last updated on 27/May/21 Commented by Panacea last updated on 27/May/21 $${plse}\:{sol} \\ $$ Terms of Service Privacy Policy Contact:…
Question Number 11078 by 3494 last updated on 10/Mar/17 $$ \\ $$$$ \\ $$$$ \\ $$$$ \\ $$ Answered by FilupS last updated on 11/Mar/17…
Question Number 76585 by Crabby89p13 last updated on 28/Dec/19 Commented by john santu last updated on 28/Dec/19 $${ratio}\:{blue}\:{area}\:{to}\:{red}\:=\:\mathrm{1}\::\:\mathrm{1} \\ $$ Answered by john santu last…
Question Number 141983 by Panacea last updated on 25/May/21 Commented by Panacea last updated on 25/May/21 $$\mathrm{plse}\:\mathrm{sol}… \\ $$$$ \\ $$ Terms of Service Privacy…
Question Number 10829 by Saham last updated on 26/Feb/17 $$\underset{{x}\rightarrow\mathrm{1}} {\mathrm{lim}}\:\int_{\:\mathrm{1}} ^{\:\mathrm{x}} \:\:\:\frac{\mathrm{e}^{\mathrm{t}^{\mathrm{2}} } \:\left(\mathrm{dt}\right)}{\mathrm{x}^{\mathrm{2}} \:−\:\mathrm{1}}\: \\ $$$$\left(\mathrm{a}\right)\:\mathrm{1}\:\left(\mathrm{b}\right)\:\mathrm{0}\:\left(\mathrm{c}\right)\:\mathrm{e}/\mathrm{2}\:\left(\mathrm{d}\right)\:\mathrm{e} \\ $$ Answered by bahmanfeshki last updated…
Question Number 10815 by fariraihmudzengerere75@gmail.c last updated on 26/Feb/17 $${Evalute}\:\:\int\left({x}^{\mathrm{2}\:} \:\:+\:\mathrm{9}\right)^{\mathrm{9}} \:{dx}\:. \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 10760 by Saham last updated on 24/Feb/17 $$\mathrm{A}\:\mathrm{block}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{2}.\mathrm{0kg}\:\mathrm{resting}\:\mathrm{on}\:\mathrm{a}\:\mathrm{smooth}\:\mathrm{horizontal}\:\mathrm{plane}\:\mathrm{is}\:\mathrm{acted} \\ $$$$\mathrm{upon}\:\mathrm{simultaneously}\:\mathrm{by}\:\mathrm{two}\:\mathrm{forces}\:\mathrm{10N}\:\mathrm{due}\:\mathrm{north}\:\mathrm{and}\:\mathrm{10N}\:\mathrm{due}\:\mathrm{east}. \\ $$$$\mathrm{The}\:\mathrm{magnitude}\:\mathrm{of}\:\mathrm{the}\:\mathrm{acceleration}\:\mathrm{produce}\:\mathrm{by}\:\mathrm{the}\:\mathrm{force}\:\mathrm{on}\:\mathrm{the}\:\mathrm{block}. \\ $$ Commented by chux last updated on 24/Feb/17 $$\mathrm{please}\:\mathrm{are}\:\mathrm{you}\:\mathrm{a}\:\mathrm{nigerian} \\…