Question Number 141750 by Algoritm last updated on 23/May/21 Answered by cherokeesay last updated on 23/May/21 $$\frac{\pi\left(\mathrm{2}{r}\right)^{\mathrm{2}} }{\mathrm{4}}\:−\:\pi{r}^{\mathrm{2}} \:\Leftrightarrow\:\frac{\pi\mathrm{4}{r}^{\mathrm{2}} }{\mathrm{4}}\:−\:\pi{r}^{\mathrm{2}} \:=\:\mathrm{0} \\ $$$$\frac{{B}_{{Area}} }{{R}_{{Area}} }\:=\:\mathrm{1}…
Question Number 10667 by Gaurav3651 last updated on 22/Feb/17 $${prove}\:{that}\:{the}\:{quadrilateral}\:{formed} \\ $$$${by}\:{angle}\:{bisectors}\:{of}\:{a}\:{cyclic}\: \\ $$$${quadrilateral}\:{is}\:{also}\:{cyclic}. \\ $$ Answered by mrW1 last updated on 22/Feb/17 $${ABCD}\:{is}\:{a}\:{convex}\:\:{quadrilateral}. \\…
Question Number 10639 by Saham last updated on 21/Feb/17 $$\mathrm{A}\:\mathrm{manometer}\:\mathrm{wire}\:\mathrm{of}\:\mathrm{lenght}\:\mathrm{60}\:\mathrm{cm}\:\mathrm{is}\:\mathrm{maintained}\:\mathrm{under} \\ $$$$\mathrm{a}\:\mathrm{tension}\:\mathrm{of}\:\mathrm{value}\:\mathrm{20V}\:\mathrm{and}\:\mathrm{an}\:\mathrm{a}.\mathrm{c}\:\mathrm{is}\:\mathrm{passed}\:\mathrm{through} \\ $$$$\mathrm{the}\:\mathrm{wire}.\:\mathrm{If}\:\mathrm{the}\:\mathrm{density}\:\mathrm{of}\:\mathrm{the}\:\mathrm{wire}\:\mathrm{is}\:\mathrm{4000kgm}^{−\mathrm{3}} \:\mathrm{and}\:\mathrm{it}\: \\ $$$$\mathrm{diamerter}\:\mathrm{is}\:\mathrm{2mm}.\:\mathrm{Calculate}\:\mathrm{the}\:\mathrm{frequency}\:\mathrm{of}\:\mathrm{the}\:\mathrm{a}.\mathrm{c} \\ $$ Commented by Saham last updated on…
Question Number 10620 by Saham last updated on 20/Feb/17 Commented by mrW1 last updated on 20/Feb/17 $${please}\:{check}: \\ $$$${after}\:{collision}\:\overset{\rightarrow} {{V}}_{{A}} =−\mathrm{5}.\mathrm{0}{i}+\mathrm{20}{j}\:\:\:\left({not}\:−\mathrm{5}.\mathrm{0}{j}+\mathrm{20}{j}\right) \\ $$$${answer}\:\left({b}\right)\:\mathrm{500}\:{J}\:\:\:\left({not}\:\mathrm{525}\:{J}\right) \\ $$…
Question Number 141608 by cherokeesay last updated on 21/May/21 Commented by cherokeesay last updated on 21/May/21 $${the}\:{area}\:{hatched}\:? \\ $$ Answered by MJS_new last updated on…
Question Number 10513 by ssparasmani@gmail.com last updated on 15/Feb/17 $${e}^{\left(−\mathrm{2}×\mathrm{10}^{−\mathrm{2}} /\mathrm{2}\right)} \\ $$ Commented by robocop last updated on 16/Feb/17 $${verifica}\:{los}\:{signos}\:{de}\:{agrupacion}\:{y}\:{te}\:{ayudo}.\:{Salu}\mathrm{2}. \\ $$ Terms of…
Question Number 10480 by ssparasmani@gmail.com last updated on 13/Feb/17 $${d}/{dx}\left(\mathrm{cos}\:^{\mathrm{2}} {xdy}/{dx}\right)=\mathrm{0} \\ $$$$ \\ $$ Answered by mrW1 last updated on 13/Feb/17 $${d}/{dx}\left(\mathrm{cos}\:^{\mathrm{2}} {xdy}/{dx}\right)=\mathrm{0} \\…
Question Number 10477 by ABCDEFGH last updated on 14/Feb/17 $${maximum}\:{and}\:{minimum}\:{value}\:{of}\: \\ $$$$\mathrm{12}{x}^{\mathrm{5}−\mathrm{5}{x}^{\mathrm{4}_{+\mathrm{40}{x}^{\mathrm{3}_{+\mathrm{6}} } } } } \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 10435 by Joel575 last updated on 09/Feb/17 Commented by Joel575 last updated on 09/Feb/17 $$\mathrm{The}\:\mathrm{side}\:\mathrm{length}\:\mathrm{of}\:\mathrm{the}\:\mathrm{square}\:\mathrm{is}\:\mathrm{1}\:\mathrm{cm}. \\ $$$$\mathrm{5}\:\mathrm{circles}\:\mathrm{have}\:\mathrm{same}\:\mathrm{radius}. \\ $$$$\mathrm{What}\:\mathrm{is}\:\mathrm{the}\:\mathrm{value}\:\mathrm{of}\:\mathrm{the}\:\mathrm{circle}'\mathrm{s}\:\mathrm{radius}? \\ $$ Answered by…
Question Number 10426 by JAZAR last updated on 10/Feb/17 $${good}\:{morning}!!!! \\ $$$${we}\:{have}\:\:{f}\left({x}\right)={x}^{\mathrm{2}} +\mathrm{2}{x}\:\:\:{g}\left({x}\right)=−\mathrm{2}{x}^{\mathrm{2}} −\mathrm{3}{x}+\mathrm{2} \\ $$$${and}\:{d}\left({m}\right)={mx}+\mathrm{2}{m} \\ $$$$\left.\mathrm{1}\right){determine}\:{the}\:{coordonate}\:{of}\:{M}_{\mathrm{1}} \:{and}\:{M}_{\mathrm{2}} \: \\ $$$${intersection}\:{points}\:{respectively}\:{of}\:\left({Cf}\right)\:{and}\:{d}\left({m}\right) \\ $$$${or}\left({Cg}\right)\:{and}\:{d}\left({m}\right) \\…