Question Number 11759 by Joel576 last updated on 31/Mar/17 $$\mathrm{A}\:\mathrm{quadrilateral}\:\mathrm{with}\:\mathrm{consecutive}\:\mathrm{sides}\:\mathrm{of}\:\mathrm{lenght}\:\mathrm{7},\:\mathrm{15},\:\mathrm{15},\:\mathrm{and}\:{d} \\ $$$$\mathrm{is}\:\mathrm{inscribed}\:\mathrm{in}\:\mathrm{a}\:\mathrm{circle}\:\mathrm{with}\:\mathrm{its}\:\mathrm{diameter}\:{d}. \\ $$$$\mathrm{Find}\:\mathrm{the}\:\mathrm{radius}\:\mathrm{of}\:\mathrm{circle} \\ $$ Answered by ajfour last updated on 31/Mar/17 Commented by…
Question Number 77280 by A8;15: last updated on 05/Jan/20 Commented by mr W last updated on 05/Jan/20 $$?????? \\ $$$${can}\:{you}\:{understand}\:{yourself}\:{sir}? \\ $$ Commented by mathmax…
Question Number 77279 by A8;15: last updated on 05/Jan/20 Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 11740 by tawa last updated on 30/Mar/17 $$\mathrm{Metal}\:\mathrm{pellets}\:\mathrm{of}\:\mathrm{mass}\:\mathrm{0}.\mathrm{1}\:\mathrm{kg}\:\mathrm{are}\:\mathrm{fired}\:\mathrm{into}\:\mathrm{an}\:\mathrm{iron}\:\mathrm{plate}\:\mathrm{of}\:\mathrm{large}\:\mathrm{mass}\:\mathrm{m} \\ $$$$\mathrm{and}\:\mathrm{specific}\:\mathrm{heat}\:\mathrm{capacity}\:\mathrm{c}\:\mathrm{at}\:\mathrm{a}\:\mathrm{temperature}\:\mathrm{of}\:\mathrm{15}°\mathrm{C}\:.\:\mathrm{25\%}\:\mathrm{of}\:\mathrm{the}\:\mathrm{kinetic} \\ $$$$\mathrm{energy}\:\mathrm{of}\:\mathrm{the}\:\mathrm{pellets}\:\mathrm{is}\:\mathrm{converted}\:\mathrm{thermal}\:\mathrm{energy}\:\mathrm{and}\:\mathrm{the}\:\mathrm{plate}\:\mathrm{temperature} \\ $$$$\mathrm{rises}\:\mathrm{to}\:\mathrm{16}°\mathrm{C}.\:\mathrm{The}\:\mathrm{average}\:\mathrm{speed}\:\mathrm{of}\:\mathrm{the}\:\mathrm{pellets}\:\mathrm{before}\:\mathrm{hitting}\:\mathrm{the}\:\mathrm{plate}\:\mathrm{was}\:? \\ $$ Terms of Service Privacy Policy Contact: info@tinkutara.com
Question Number 77213 by A8;15: last updated on 04/Jan/20 Commented by A8;15: last updated on 04/Jan/20 $${prove} \\ $$$$\alpha= \\ $$ Commented by A8;15: last…
Question Number 11632 by Joel576 last updated on 29/Mar/17 Answered by sandy_suhendra last updated on 29/Mar/17 Commented by sandy_suhendra last updated on 29/Mar/17 $$\mathrm{Area}\:\Delta\mathrm{AOB}\:+\:\mathrm{Area}\:\Delta\:\mathrm{BPC} \\…
Question Number 77143 by Boyka last updated on 03/Jan/20 Commented by mr W last updated on 04/Jan/20 $${Master}\:{sir}: \\ $$$${if}\:{you}\:{don}'{t}\:{understand}\:{the}\:{answer} \\ $$$${i}\:{have}\:{given}\:{in}\:{your}\:{earlier}\:{post}, \\ $$$${you}\:{can}\:{tell}\:{me}\:{what}\:{you}\:{don}'{t} \\…
Question Number 11594 by JAZAR last updated on 28/Mar/17 $${please}\:{how}\:{can}\:{demonstred}\: \\ $$$${sin}\left(\mathrm{2}{x}\underset{} {\right)}/{cos}\left(\mathrm{2}{x}\right)=\mathrm{2}{sin}\left(\mathrm{2}{x}\right) \\ $$ Answered by mrW1 last updated on 28/Mar/17 $${that}'{s}\:{not}\:{true}! \\ $$$$\mathrm{sin}\:\left(\mathrm{2}{x}\right)/\mathrm{cos}\:\left(\mathrm{2}{x}\right)=\mathrm{tan}\:\left(\mathrm{2}{x}\right)\neq\mathrm{2sin}\:\left(\mathrm{2}{x}\right)…
Question Number 77091 by Boyka last updated on 03/Jan/20 Commented by john santu last updated on 03/Jan/20 $${sir}\:{i}\:{don}'{t}\:{read}\:{your}\:{used}\:{symbol} \\ $$ Commented by Boyka last updated…
Question Number 142560 by ajfour last updated on 02/Jun/21 Answered by 1549442205PVT last updated on 02/Jun/21 $$\mathrm{put}\:\mathrm{AC}=\mathrm{x},\mathrm{CP}=\mathrm{y}\Rightarrow\mathrm{AO}.\mathrm{OB}=\mathrm{OP}^{\mathrm{2}} \\ $$$$\Leftrightarrow\sqrt{\mathrm{x}^{\mathrm{2}} +\mathrm{c}^{\mathrm{2}} }\left(\mathrm{1}−\sqrt{\mathrm{c}^{\mathrm{2}} +\mathrm{x}^{\mathrm{2}} }\right)=\mathrm{c}^{\mathrm{2}} +\mathrm{y}^{\mathrm{2}} \left(\mathrm{1}\right)…