Question Number 74137 by MASANJAJ last updated on 19/Nov/19 Commented by TawaTawa last updated on 19/Nov/19 $$\left(\mathrm{16a}\right) \\ $$$$\:\:\:\:\:\:\mathrm{5}\:\mathrm{painters}\:\mathrm{will}\:\mathrm{spend}\:\mathrm{less}\:\mathrm{hours} \\ $$$$\therefore\:\:\:\:\:\:\:\:\:\mathrm{1}\:\mathrm{painter}\:\:\:=\:\:\mathrm{2}\:×\:\mathrm{6}\:\:=\:\:\mathrm{12}\:\mathrm{hrs} \\ $$$$\therefore\:\:\:\:\:\:\:\:\:\:\:\:\:\:\:\mathrm{5}\:\mathrm{painters}\:\:\:\:=\:\:\:\frac{\mathrm{12}}{\mathrm{5}}\:\mathrm{hrs} \\ $$…
Question Number 8582 by thomas last updated on 16/Oct/16 $$\mathrm{9}×\mathrm{9} \\ $$ Answered by Rasheed Soomro last updated on 17/Oct/16 $$\mathrm{9}×\mathrm{9} \\ $$$$=\left(\mathrm{10}−\mathrm{1}\right)\left(\mathrm{10}−\mathrm{1}\right) \\ $$$$=\left(\mathrm{10}−\mathrm{1}\right)^{\mathrm{2}}…
Question Number 139649 by mnjuly1970 last updated on 30/Apr/21 Commented by mr W last updated on 30/Apr/21 $$\frac{{red}}{{green}}=\frac{\mathrm{6}}{\mathrm{5}} \\ $$ Answered by mr W last…
Question Number 74112 by TawaTawa last updated on 19/Nov/19 Answered by mind is power last updated on 19/Nov/19 $${let}\:{l}={side}\:{of}\:{squar}\Rightarrow{l}^{\mathrm{2}} +\frac{{l}}{\mathrm{2}}\left({x}+{z}+{y}\right)=\frac{\left({z}+{l}+{y}\right)}{\mathrm{2}}\left({l}+{x}\right) \\ $$$$\Leftrightarrow\mathrm{2}{l}^{\mathrm{2}} +{l}\left({x}+{y}+{z}\right)={l}\left({z}+{y}+{l}\right)+{x}\left({z}+{l}+{y}\right) \\ $$$$\Rightarrow\mathrm{2}{l}^{\mathrm{2}}…
Question Number 74087 by mr W last updated on 19/Nov/19 $$\left({Q}\mathrm{73828}\right) \\ $$$${prove}\:{that}\:{no}\:{cube}\:{exists}\:{whose}\:{corners} \\ $$$${are}\:{located}\:{on}\:{all}\:{faces}\:{of}\:{an}\:{other}\:{cube}. \\ $$ Commented by mr W last updated on 18/Nov/19…
Question Number 8528 by suci last updated on 14/Oct/16 $${A}\left(\mathrm{2},{b}\right)\:{translation}\:{T}_{\mathrm{1}} =\begin{pmatrix}{−\mathrm{3}}\\{\:\:\:{b}}\end{pmatrix} \\ $$$${followed}\:{by}\:{translation}\:{T}_{\mathrm{2}} =\begin{pmatrix}{{a}}\\{\mathrm{4}}\end{pmatrix} \\ $$$${A}'=\left({b}−\mathrm{1},{a}−\mathrm{3}\right) \\ $$$${determine}\:{the}\:{value}\:{of}\:{a}+{b}=…? \\ $$ Answered by sandy_suhendra last updated…
Question Number 139545 by aliibrahim1 last updated on 28/Apr/21 Answered by mr W last updated on 28/Apr/21 Commented by mr W last updated on 28/Apr/21…
Question Number 8471 by PradipGos. last updated on 12/Oct/16 $$\underset{−\infty} {\overset{\infty} {\int}}{e}^{−\mathrm{2}\mid{x}\mid{d}\underset{} {{x}}} \:\:\:\:\:\:?\:\: \\ $$ Commented by FilupSmith last updated on 12/Oct/16 $$\mathrm{Do}\:\mathrm{you}\:\mathrm{mean}: \\…
Question Number 139506 by I want to learn more last updated on 28/Apr/21 Commented by I want to learn more last updated on 28/Apr/21 $$\mathrm{Find}\:\mathrm{the}\:\mathrm{double}\:\mathrm{line}\:\mathrm{angle}.…
Question Number 8427 by tawakalitu last updated on 10/Oct/16 $$\mathrm{In}\:\mathrm{a}\:\mathrm{circle}\:\mathrm{PQRST}\:\mathrm{center}\:\mathrm{O},\:\mathrm{PQRS}\:\mathrm{is}\:\mathrm{a}\: \\ $$$$\mathrm{cyclic}\:\mathrm{quadrilateral}\:\mathrm{and}\:\mathrm{T}\:\mathrm{is}\:\mathrm{on}\:\mathrm{the}\:\mathrm{circle}. \\ $$$$\mathrm{QS}\:\mathrm{is}\:\mathrm{a}\:\mathrm{diameter}\:\mathrm{and}\:\mathrm{angle}\:\mathrm{QOR}\:\mathrm{is}\:\mathrm{86}° \\ $$$$\mathrm{if}\:\mathrm{PTQ}\:\mathrm{is}\:\mathrm{28}°\:.\:\mathrm{Find}\:\mathrm{the}\:\mathrm{angles}\:\mathrm{of}\:\mathrm{the}\: \\ $$$$\mathrm{quadrilateral}\:\mathrm{PQRS}. \\ $$ Answered by sandy_suhendra last updated…